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Chemistry MCQs for NEET — Practice Questions with Answers

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$H_{2} O_{2}$ when added to a solution containing $K M n O_{4} a n d H_{2} S O_{4}$ acts:

as an oxidizing agent

as a reducing agent

both as an oxidizing as well as a reducing agent

none of these

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$H_{2} O_{2}$ converts potassium ferrocyanide to ferricyanide. The change observed in the oxidation state of iron is:

$F e^{2 +} \to F e^{3 +}$

$F e \to F e^{2 +}$

$F e^{3 +} \to F e^{2 +}$

$F e^{2 +} \to F e^{+}$

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Explanation

An acid solution of potassium ferrocyanide is oxidised by hydrogen peroxide to potassium ferricyanide

2K4FeC6N6 + H2O2 = 2K3FeC6N6 + 2KOH

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$H_{2} O_{2}$ acts as a reducing agent in its:

reaction with a ferrous salt

reaction with iodides

reaction with lead sulphide

reaction with $K M n O_{4}$ in acid medium

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$H_{2} O_{2}$ turns an acidified solution of ........... to orange-red.

$B a O_{2}$

$P b O_{2}$

$N a_{2} O_{2}$

$T i O_{2}$

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Explanation

Hydrogen peroxide on treatment with a acidified solution of Titanium salt gives a Yellow or Orange colour due to the formation of pertitanic acid.

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$H_{2} O_{2}$ is prepared in the laboratory when:

$M n O_{2}$ is added to dilute cold $H_{2} S O_{4}$

$B a O_{2}$ is added to $C O_{2}$ bubbling through cold water

$P b O_{2}$ is added to an acidified solution of $K M n O_{4}$

$N a_{2} O_{2}$ is added to boiling water

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Explanation

(2)

Hydrogen peroxide can be prepared in the laboratory by the action of ice cold, dilute sulphuric acid on sodium peroxide or hydrated barium peroxide (BaO2. 8H2O). Most of the sodium sulphate separates out on cooling as crystals of Na2SO4.

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$H_{2} O_{2}$ on treatment with chlorine gives:

$H_{2}$

oxygen

HOCl

$C l O_{2}$

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For the bleaching of hair, the substance used is:

$S O_{2}$

bleaching powder

$H_{2} O_{2}$

$O_{3}$

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Explanation

Hydrogen peroxide is one of the most common lightening agents. The peroxide is used in an alkaline solution, which opens the hair shaft to allow the peroxide to react with the melanin

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A given solution of $H_{2} O_{2}$ is 30 volume. Its concentration in terms of molarity is:

9.1 M

2.68 M

2.5 M

26.8 M

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Explanation

Volume strength is 30.

Molarity = Volume strength / 11.2 = 30/ 11.2 = 2.68M

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Decolourisation of acidified potassium permanganate occurs when $H_{2} O_{2}$ is added to it. This is due to:

oxidation of $K M n O_{4}$

reduction of $K M n O_{4}$

both oxidation and reduction of $K M n O_{4}$

none of these

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The percentage by mass of hydrogen in $H_{2} O_{2}$ is:

6.25

5.88

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