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Chemistry MCQs for NEET — Practice Questions with Answers

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Sodium reacts with water less vigorously than potassium because-

It has higher atomic weight

It is less electropositive

It is more electronegative

It is a metal

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Explanation

(B) The reactivity of alkali metals increases down the groups.

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The density of-

Na > K

Na = K

K > Na

Li > K

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Explanation

(A). The densities of elements of group 1 are quite low (Li = 0.534 g/cc, Na = 0.972, K = 0.559, Rb = 1.53, Cs = 1.903).
It increases gradually in moving from Li to Cs. However potassium is lighter than sodium probably due to an unusual increase in atomic size of potassium.

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Which of the following is amphoteric –

$B e {(O H)}_{2}$

$C a {(O H)}_{2}$

$S r {(O H)}_{2}$

$B a {(O H)}_{2}$

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Explanation

(A) $B e {(O H)}_{2}$ reacts with both acid and bases or dissolves in acids as well as in alkalies.

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The reason for the lower basicity of alkaline earth metals than alkali metals is.

Alkali metals form ionic compounds

The bond of oxygen is more for alkali metals

The electropositivity of alkali metals is more than alkaline earth metals

The electropositivity of alkali metals is less than alkaline earth metals

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Explanation

(C). Because alkali metals are more electropositive than alkaline earth metals.

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In $K^{+} F^{-}$ ionic radius of $F^{-}$ is more while atomic radius of $K^{+}$ is –

Less than $F^{-}$

More than $F^{-}$

Equal to $F^{-}$

None of these

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Explanation

(B). Alkali metals have the largest atomic sizes in their corresponding periods.K⁺ = 138 pm,

F^{- _{133 pm}}

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Lattice energy is lowest for –

LiF

NaCl

KBr

CsI

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Explanation

(D). Due to large size of Cs and I atoms.

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MgO is a-

Acidic oxide

Basic oxide

Neutral oxide

Amphoteric oxide

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Explanation

(B). It is a basic oxide and hence reacts with acids to form salts.

$M g O + 2 H C l \to M g C l_{2} + H_{2} O$

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Which of the following statements is wrong ?

Lithium nitrate on heating gives lithium nitrite and $O_{2}$ .

Sodium oxide, $N a_{2} O$ is obtained on heating sodium azide with sodium nitrite.

Potassium cyanide dissolves silver in presence of air or $O_{2}$ .

Potassium formate is formed when moist $C O_{2}$ reacts with potassium hydride.

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Explanation

(A). $4 L i N O_{3} \to 2 L i_{2} O + 4 N O_{2} + O_{2}$

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Ionic conductances of hydrated M+ ions are in the order-

$L i^{+} (a q) > N a^{+} (a q) > K^{+} (a q) > R b^{+} (a q) > C s^{+} (a q)$

$L i^{+} (a q) > N a^{+} (a q) < K^{+} (a q) < R b^{+} (a q) < C s^{+} (a q)$

$L i^{+} (a q) > N a^{+} (a q) > K^{+} (a q) > R b^{+} (a q) < C s^{+} (a q)$

$L i^{+} (a q) < N a^{+} (a q) < K^{+} (a q) < R b^{+} (a q) < C s^{+} (a q)$

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Explanation

(D). Due to high charge density of $L i^{+}$ is attracts more water molecules and becomes bulky so the ionic conductances of $M^{+}$ ions increase from $L i^{+}$ ion to $C s^{+}$ ion.

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Which of the following halides has the highest melting point-

NaCl

KCl

NaBr

NaF

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Explanation

(D). Apply Fazan’s rule.

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Yes. You can attempt every Chemistry question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.