2-methylpent-3-ene is a chiral because it has:
2-methylpent-3-ene does not have a center or plane of symmetry. It has a chiral carbon (C2) due to the presence of four different groups attached to it, making the molecule chiral or optically active.
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2-methylpent-3-ene is a chiral because it has:
2-methylpent-3-ene does not have a center or plane of symmetry. It has a chiral carbon (C2) due to the presence of four different groups attached to it, making the molecule chiral or optically active.
The (R)- and (S)-enantiomers of an optically active compound differ in
(c) R and S forms of an optically active compounds differ in their behaviour towards plane polarised light. The species which rotate the plane of polarised light toward right is called R-form (rectus form) or d-form (dextro-form) and the species which rotate the plane of polarised light towards left is known as S-form (sinister-form) or L-form (laevo-form).
The cylindrical shape of an alkyne is due to
(d) In alkynes C≡C is present, in such bond one sigma and two π C-C bonds are present. Sigma bond is formed by sp-hybrid orbitals whereas π-bonds are formed by unhybridised orbitals.
Hence, it shows cylindrical shape.
What is decreasing order of basicity of 1°, 2° and 3° ethyl amines and ammonia?
(d) As the number of alkyl groups increases, the electron density on nitrogen atom also increases, so the basic character increases but 3° amines are less basic than 2° amines due to steric hindrance of 3° amines, so the correct order of basicity is
Ammonia < 1 < 2 <3
NH3<C2H5NH2<(C2H5)3N<(C2H5)2NH
The shortest C-C bond distance is found in
(d) Acetylene has shortest C-C bond length because it has C≡C triple bond. The bond length follows the following order
C-C>C=C>C≡C
Which of the following is more basic than aniline?
(d) Benzyl amine, C6H5CH2-N..H2 is more basic than aniline because benzyl group (C6H5CH2-) is electron donating group due to +I-effect. So, it is able to increase the electron density of N of -NH2 group. Thus, due to higher electron density, rate of donation of free pair of electron is increased, i.e. basic character is hhigher. Phenyl and nitro group are electron attractive groups, so they are able to decrease the electron density of N of -N..H2 group. Hence, they are less basic than aniline.
Which one of the following has the shortest carbon-carbon bond length?
(c) Ethyne (acetylene) have shortest C-C bond length because it has CC bond. The bond length follows the following order
CC <C=C<C-C
Which of the following represents the correct order of acidity in the given compounds?
(c) The acidity of halogenated acid increases with increase in electronegativity of the halogen present. So, the correct order is order is F > Ce >Br
FCOOH > ClCOOH > BrCOOH > COOH
Ethanol and dimethyl ether form a pair of functional isomers. The boiling point of ethanol is higher than that of dimethyl ether due to the presence of
Ethanol has a hydroxyl (-OH) group that can participate in hydrogen bonding, whereas dimethyl ether does not have any hydrogen atoms attached to highly electronegative atoms. This intermolecular hydrogen bonding in ethanol results in stronger attractive forces, leading to a higher boiling point.
Among the following the strongest acid is
(c) We know that, inductive effect decreases rapidly with distance. Inductance effect distance depending factor. As the distance of Cl-atom increases the acidic character decreases.
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