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Chemistry MCQs for NEET — Practice Questions with Answers

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Products of the following reaction

${CH}_{3} C \equiv C . {CH}_{2} {CH}_{3} \to_{(ii) Hydrolysis}^{(i) O_{3}}$ ... are

${CH}_{3} CHO$ + ${CH}_{3} {CH}_{2} CHO$

${CH}_{3} COOH$ + ${CH}_{3} {COCH}_{3}$

${CH}_{3} COOH$ + $HOOC . {CH}_{2} {CH}_{3}$

${CH}_{3} COOH$ + ${CO}_{2}$

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Which of the following compounds with molecular formula, $C_{5} H_{10}$ yields acetone on ozonolysis?

2-methyl-2-butene

3-methyl-1-butene

Cyclopentane

2-methyl-1-butene

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Explanation

(a) 2-methyl-2-butene (molecular formula $C_{5} H_{10}$ ) yields acetone on ozonolysis.

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Ozonolysis ( $O_{3}$ , $H_{2} O$ ) of, ${CH}_{3} - \underset{{CH}_{3}}{\underset{|}{CH}} - C \equiv C - {CH}_{3}$ gives :

${CH}_{3} \underset{{CH}_{3}}{\underset{|}{CH}} COOH$ + ${CH}_{3} COOH$

${CH}_{3} \underset{{CH}_{3}}{\underset{|}{CH}} CHO$ + ${CH}_{3} CHO$

${CH}_{3} \underset{{CH}_{3}}{\underset{|}{CH}} CHO$ + ${CH}_{3} COOH$

none of the above

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Explanation

The aldehydes formed are oxidized by $H_{2} O_{2}$ formed during hydrolysis.

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When 3,3-dimethyl-2-butanol is heated with conc. $H_{2} {SO}_{4}$ , the major product obtained is

2,3-dimethyl-2-butene

3,3-dimethyl-2-butene

2,3-dimethyl-1-butene

cis and trans-isomers of 2,3-dimethyl-2-butene

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Silver acetylide when heated with HCl gives:

$C_{2} H_{2}$

$H_{2}$

$C_{2} H_{4}$

$C_{6} H_{6}$

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Explanation

(a) Ag $C \equiv C$ Ag $\overset{HCl}{\to}$ $CH \equiv CH$

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Alkene-1 on hydroboration followed with action of $H_{2} O_{2}$ gives:

alkanol-2

alkanol-1

alkanal

alkanone

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Explanation

(b) $6 R - CH = {CH}_{2} \overset{B_{2} H_{6}}{\to}$ $2 {({RCH}_{2} {CH}_{2})}_{3} B_{2}$

$2 {({RCH}_{2} {CH}_{2})}_{3} B_{2}$ $\overset{6 H_{2} O_{2}}{\to}$ ${RCH}_{2} {CH}_{2} OH$ + $2 H_{3} {BO}_{3}$

This process always gives alkanol-1 from alkane-1.

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Which of the following reagents will be able to distinguish between 1-butyne and 2-butyne?

${NaNH}_{2}$

HCl

$O_{2}$

${Br}_{2}$

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Explanation

(a) ${NaNH}_{2}$ is used to distinguish between 1-butyne and 2-butyne.

${CH}_{3} {CH}_{2} C \equiv CH \overset{{NaNH}_{2}}{\to}$ ${CH}_{3} {CH}_{2} C \equiv CNa + \frac{1}{2} H_{2} ↑$

${CH}_{3} - C \equiv C - H \overset{{NaNH}_{2}}{\to}$ No reaction

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Which reagent distinguish propyne and propene?

Alkaline ${KMnO}_{4}$

${Cu}_{2} {Cl}_{2}$ + ${NH}_{4} Cl$

${Br}_{2}$ water

${Cu}_{2} {Cl}_{2}$ + ${NH}_{4} OH$

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Explanation

Propyne has acidic hydrogen and it reacts with ${Cu}_{2} {Cl}_{2}$ + ${NH}_{4} OH$ to form red ppt. Propene can not react.

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Which alkene has smallest heat of hydrogenation?

${CH}_{3} - CH = CH - {CH}_{3}$

${({CH}_{3})}_{2} C = CH - {CH}_{3}$

${CH}_{2} = CH - {CH}_{2} - {CH}_{3}$

${CH}_{3} - CH = CH - CH {({CH}_{3})}_{2}$

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Explanation

Higher is the stability of alkene, smaller is the heat of hydrogenation.

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The correct order of relatives rates of hydrogenation of alkenes is

Ethylene > propene > 2-butene > 2-methyl-2-butene

2-methyl-2-butene > 2-butene > Propene > Ethylene

2-butene > propene > ethylene > 2-methyl-2-butene

Propene > 2-butene > ethylene > 2-methyl-2-butene

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Explanation

Higher is the stability of alkane, smaller is the heat of hydrogenation.

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