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Chemistry MCQs for NEET — Practice Questions with Answers

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n-Butylbenzene on oxidation with hot alkaline KMnO₄ gives:-

benzoic acid

butanoic acid

benzyl alcohol

benzaldehyde

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Explanation

(a) Those carbon having α-hydrogen convert into benzoic acid.

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Consider the following sequence of reactions.

$C_{6} H_{6} + {CH}_{3} CH = {CH}_{2} \to_{heat}^{H_{3} {PO}_{4}} A \to_{2 . H_{3} O^{+}, heat}^{1 . O_{2}, Heat} B + C$

The products (B) and (C) are

benzaldehyde and acetaldehyde

benzoic acid and acetic acid

phenol and propionaldehyde

phenol and acetone

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Explanation

(d) Industrial method for preparation for phenol which is known as cumen-hydoperoxide rearrangement.

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$Ph - {CO}_{2} H \overset{{SOCl}_{2}}{\to} A \overset{{Me}_{2} NH}{\to} B \overset{(c)}{\to} Ph - CHO$ , unknown reagent (c) is:

LiALH₄

NaBH₄

LiAlH₄(t-BuO)₃

PCC/CH₂CL₂

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p-Toluidine reacts with benzene diazonium chloride to form compound, which on boiling with aq. H₂SO₄ give .......... products:

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Which of the following benzene ring substituents is deactivating but ortho-para directing?

-N=O

-OCH₃

-COCH₃

-NO₂

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Explanation

(a) $- \overset{. .}{N} = O group is + M and - M .$

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Which of the following substance will increase the acidity of phenol?

Dil. H₂SO₄

Dil. HCl

Conc. H₂SO₄

Conc. CH₃COOH

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Explanation

Concentrated sulfuric acid (conc. H2SO4) increases the acidity of phenol by protonating it, forming the phenoxonium ion. This makes phenol a stronger acid due to the stabilization of the phenoxide anion by delocalization of the negative charge over the benzene ring.

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Give a simple test to differentiate cyclohexane and cyclohexene :

Br₂/H₂0

Baeyer's reagent

Tollen's reagent

Both (a) and (b)

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Explanation

(d) (a) and (b) are test for alkene.

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Partial oxidation of methane with Ni/Al₂O₃ catalyst gives:

HCHO

HCOOH

H₂O and CO₂

CO and H₂O

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Explanation

${CH}_{4} \overset{[O]}{\to} H_{2} O + CO$

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Identity Z in the sequence of reactions,
HBr/H₂O₂
CH₃CH₂CH=CH₂→Y
C₂H₅ONA→Z

CH₃-(CH₂)₃-O-CH₂CH₃

(CH₃)₂CH₂-O-CH₂CH₃

CH₃(CH₂)₄-O-CH₃

CH₃CH₂-CH(CH₃)-O-CH₂CH₃

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Explanation

HBr/H₂O₂
CH₃CH₂CH=CH₂→CH₃CH₂CH₂CH₂Br
Anti-Markownikoff's rule
C₂H₅ONa
CH₃CH₂CH₂CH₂Br→CH₃CH₂CH₂CH₂OC₂H₅
SN² reaction

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Which of the following organic compounds has same hybridisation as its combustion product -(CO₂)?

Ethane

Ethyne

Ethene

Ethanol

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Explanation

Ethyne (C₂H₂) contains two carbon atoms that are sp hybridized, just like in CO₂. The other options have different hybridization states for their carbon atoms.

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