Ka for $CH_3COOH$ at $ 25 ^\circ C $ is $ 1.754 \times 10^{–5} $ . At $ 50 ^\circ C$ , Ka is $ 1.633 \times 10^{–5} $ What will be value of $ OS^ \circ $ for the ionisation of $CH_3COOH$?
$ ( G ^ \circ )_{298} = -2.303 RT log K = - 2.303 \times 8.314 \times 298 \times log (1.754 \times 10 ^ {-5} ) = 27194 J $ $ ( G^ \circ )_{323} = 2.303 \times 8.314 \times log ( 1.633 \times 10 ^ {-5} = 298 \triangle S ^ \circ $ $ 96.44 J / mol K $