Chemistry MCQs for NEET — Practice Questions with Answers

Practice free Chemistry NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Register free to filter questions

Ka for $CH_3COOH$ at $ 25 ^\circ C $ is $ 1.754 \times 10^{–5} $ . At $ 50 ^\circ C$ , Ka is $ 1.633 \times 10^{–5} $ What will be value of $ OS^ \circ $ for the ionisation of $CH_3COOH$?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ ( G ^ \circ )_{298} = -2.303 RT log K = - 2.303 \times 8.314 \times 298 \times log (1.754 \times 10 ^ {-5} ) = 27194 J $ $ ( G^ \circ )_{323} = 2.303 \times 8.314 \times log ( 1.633 \times 10 ^ {-5} = 298 \triangle S ^ \circ $ $ 96.44 J / mol K $

$ C_2H_6 (g) + 3.5 O_2 (g) \rightarrow 2CO_2 (g) + 3H_2O (g) $ $ \triangle S_{vap} (H_2O, l)$ = $ x_1 cal K^{–1} (boiling point + T_1) $ $ \triangle Hf (H_2O, l)$ = $ x_2$ $ \triangle Hf (CO_2)$ = $ x_3 $ $ \triangle Hf (C_2H_6) $ = $ x_4 $ Hence $ \triangle H $ for the reaction is –

You've reached today's free limit of 20 questions. Log in to keep practising for free.

$ C (s) + O_2 (g) \rightarrow CO_2, (g)$ ; OH = –94.3 kcal/mol $ CO (g) + O_2(g) \rightarrow CO_2 (g)$ ; O H = – 67.4 kcal/mol $ O_2(g) \rightarrow 2O (g)$ ; OH = 117.4 kcal/mol $ CO (g) \rightarrow C (g) + O(g)$ ; OH = 230.6 kcal/mol Calculate OH for $ C (s) \rightarrow C (g) $ in kcal/mol.

You've reached today's free limit of 20 questions. Log in to keep practising for free.

The difference between OH and OE on a molar basis for the combustion of n–octane at $ 25 ^\circ C $ would be : $ 25 ^ \circ C $

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ \triangle H - \triangle E = -4.5 \times 8.315 \times 298 J = - 11.15 kJ $

What is the work done against the atmosphere when 25 grams of water vaporizes at 373 K against a constant external pressure of 1 atm ? Assume that steam obeys perfect gas laws. Given that the molar enthalpy of vaporization is 9.72 kcal/mole, what is the change of internal energy in the above process ?

You've reached today's free limit of 20 questions. Log in to keep practising for free.

In the reaction $ CS_2 (l) + 3O_2 (g) \rightarrow CO_2 (g) + 2SO_2 (g) OH = –265 kcal $ The enthalpies of formation of $ CO_2 and SO_2 $ are both negative and are in the ratio 4 : 3. The enthalpy of formation of $ CS_2 $ is + 26 kcal/mol. Calculate the enthalpy of formation of $ SO_2 $ .

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ Cs_2 (l) + 3 O_2 (g) \rightarrow Co_2 (g) + 2 SO_2 $ $ let \triangle H_f ( CO_2 , g ) = 4x and \triangle H_ f ( SO_2 , g ) = 3x $ $ \triangle H_{reaction} = \triangle H_f ( CO_2 , g ) = 2 \triangle H_f ( SO_2 .g ) - \triangle H_f ( CS_2 ) $ $ - 265 = 4x + 6x - 26 $ $ x = -23.9 $ $ \therefore \triangle H_f ( SO_2 , g ) = 3x = -71.7 Kcal / mol . $

The bond dissociation energy of gaseous $H_2, Cl_2 $ and HCl are 104, 58 and 103 kcal mol– 1 respectively. The enthalpy of formation for HCl gas will be

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

Given $ H_2 (g) \rightarrow HCl (g); \triangle H = 104 kcal ...(1) $ $ Cl_2 (g) \rightarrow 2Cl(g); \triangle H = 58 kcal ...(2) $ $ HCl (g) \rightarrow H(g) + Cl(g); \triangle H = 103 kcal ...(3) $ Heat of formation for HCl $ H_2 (g) + Cl_2 (g) \rightarrow HCl (g); \triangle H = ? $ Divide equation (1) and (2) by 2, and then add $ H_2 (g) + Cl_2 (g) \rightarrow H(g) + Cl(g); \triangle H = 81 kcal...(4) $ Subtracting equation (3) from equation (4) $ HCl (g) \rightarrow H(g) + Cl(g) ; \triangle H = 103 kcal ...(3) $ – – – –

$ H_2 (g) + Cl_2 (g) HCl(g); \triangle H = -22.0 kcal $ $ \therefore Enthalpy of formation of HCl gas = – 22.0 kcal $

$ AB, A_2 $ and $ B_2 $ are diatomic molecules. If the bond enthalpies of $A_2$, AB & $B_2 $ are in the ratio 1 : 1 : 0.5 and enthalpy of formation of AB from $A_2$ and $B_2$ is – 100 kJ/mol–1. What is the bond enthalpy of $A_2$ .

You've reached today's free limit of 20 questions. Log in to keep practising for free.

One mole of a gas occupying $3 dm^3 $ expands against constant external pressure of 1 atm to a volume of $ 13 dm^3 $ . The work done is –

You've reached today's free limit of 20 questions. Log in to keep practising for free.

The heat of formation of liquid methyl alcohol is kilojoule per mole using the following data will be [Heat of vaporisation of liquid methyl alcohol = 38 kJ/mol. Heat of formation of gaseous atoms from the elements in their standard states : H, 218 kJ/mol; C, 715 kJ/mol; O, 249 kJ/mol. Average bond energies : C – H, 415 kJ/mol; C – O, 356 kJ/mol O – H, 463 kJ/mol.]

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Chemistry question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.