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Chemistry MCQs for NEET — Practice Questions with Answers

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Arrange the following species in the increasing order of their magnetic properties.

${VCl}_{3}$ ${VOSO}_{4}$ ${Na}_{3} {VO}_{4}$ $[V {(H_{2} O)}_{6}] {SO}_{4} . H_{2} O$

I II III IV

III<II<I<IV

III<IV<II<I

II<III<I<IV

IV<I<II<III

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Explanation

(A)

(I) ${VCl}_{3};$ ${}_{23}V_{3 +}; {[Ar]}^{18} 3 d^{2} = 2$ unpaired electrons.

(II) ${VO}^{2 +}; V^{4 +}; {[Ar]}^{18} 3 d^{2} = 1$ unpaired electrons.

(III) ${[{VO}_{4}]}^{3 -}; V^{5 +}; {[Ar]}^{18} 3 d^{0} =$ no unpaired electrons.

(IV) ${[V {(H_{2} O)}_{6}]}^{2 +}; V^{2 +}; {[Ar]}^{18} 3 d^{3} = 3$ unpaired electrons.

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Which of the following increasing order of oxidising power is correct for the following species?

${VO}_{2}^{+}, {MnO}_{4}^{-}, {Cr}_{2} {O_{7}}^{2 -}$

${VO}_{2}^{+} < {Cr}_{2} {O_{7}}^{2 -} < {MnO}_{4}^{-}$

${VO}_{2}^{+} < {MnO}_{4}^{-} < {Cr}_{2} {O_{7}}^{2 -}$

${Cr}_{2} {O_{7}}^{2 -} < {VO}_{2}^{+} < {MnO}_{4}^{-},$

${Cr}_{2} {O_{7}}^{2 -} < {MnO}_{4}^{-} < {VO}_{2}^{+}$

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Explanation

(A) This is due to the increasing stability of the lower species to which they are reduced.

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In which of the following oxoanions the oxidation state of the central atom is not the same as that of its group number in the periodic table?

${MnO}_{4}^{}^{-}$

${Cr}_{2} O_{7}^{2 -}$

${VO}_{4}^{3 -}$

${FeO}_{4}^{2 -}$

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Explanation

(D)

(A) ${MnO}_{4}^{-} = + 7; {[Ar]}^{18} 3 d^{5} 4 s^{2} = 7 .$ (B) ${Cr}_{2} O_{7}^{2 -} = + 6; {[Ar]}^{18} 3 d^{5} 4 s^{1} = 6 .$

(C) ${VO}_{4}^{3 -} = + 5; {[Ar]}^{18} 3 d^{3} 4 s^{2} = 5 .$ (D) ${FeO}_{4}^{2 -} = + 6; {[Ar]}^{18} 3 d^{6} 4 s^{2} = 8 .$

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At $300 ° C, {FeCl}_{3} :$

Decomposes into ${FeCl}_{2} and {Cl}_{2} .$

Decomposes into $Fe and {Cl}_{2} .$

Sublimes go give liquid ${FeCl}_{3}$

Sublimes to give gaseous dimmer ${({FeCl}_{3})}_{2} .$

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Explanation

True statement, $2 {FeCl}_{3} \overset{300 ° C}{\to} {({FeCl}_{3})}_{2} (g)$

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Anhydrous ferric chloride is prepared by

Heating hydrated ferric chloride at a high temperature in a stream of air.

Heating metallic iron in a stream of dry chlorine gas.

Reaction of ferric oxide with HCl (aq).

Reaction of metallic iron with HCl (aq).

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Explanation

(B)

(B) $2 Fe + 3 {Cl}_{2} \overset{}{\to} 2 {FeCl}_{3} (anhydrous); (A), (C), (D)$ do not give anhydrous ${FeCl}_{3}$ but

hydrated ${FeCl}_{3} .$

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Anhydrous ferrous sulphate on heating gives :

Both ${SO}_{2} and {SO}_{3}$

${SO}_{2} only$

${SO}_{3} only$

${Fe}_{2} {({SO}_{4})}_{3} only$

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${FeCl}_{3} . 6 H_{2} O + C {({CH}_{3})}_{2} {({CH}_{3} O)}_{2} \to Products$

Reaction products are :

${FeCl}_{3}, {CH}_{3} OH and {CH}_{3} {COCH}_{3}$

$({CH}_{3} O) Fe, HCl and H_{2} O$

${FeCl}_{2}, HCl and {CH}_{3} {COCH}_{3}$

$Fe {(OH)}_{3}, {FeCl}_{3} and {CH}_{3} {COCH}_{3}$

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Explanation

(A) ${FeCl}_{3} . 6 H_{2} O + CH - {C_{|}^{|}}_{{OCH}_{3}}^{{OCH}_{3}} - {CH}_{3} \to {FeCl}_{3} + 12 {CH}_{3} OH + 6 {CH}_{3} {COOH}_{3}$

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Excess of Kl reactions with ${CuSO}_{4}$ solution and ${Na}_{2} {SO}_{4}$ solution is added to it. Which of the following statement is incorrect for this reaction ?

Evolved $I_{2}$ is reduced

${Cul}_{2}$ is formed

${Na}_{2} S_{2} O_{3}$ is oxides

${Cu}_{2} l_{2}$ is formed.

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Explanation

(B)

$2 {CuSO}_{4} + 4 Kl \overset{}{\to} 2 K_{2} {SO}_{4} + {Cu}_{2} I_{2} + I_{2} 2 {Na}_{2} S_{2} O_{3} + I_{2} \overset{}{\to} {Na}_{2} S_{4} O_{6} + 2 NaI; {CuI}_{2} is not formed according to following reaction . 2 {CuI}_{2} (unstable) \overset{}{\to} {Cu}_{2} I_{2} + I_{2} .$

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Select the correct statement :

${PH}_{3}$ reduces ${AgNO}_{3}$ to metallic Ag.

Organic tissues turn ${AgNO}_{3}$ black by reducing it to Ag.

$AgCN$ is soluble in $KCN$ .

All are correct statements.

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Explanation

(D)

(A) ${AgNO}_{3} + {PH}_{3} \overset{}{\to} Ag ↓ + {HNO}_{3} + H_{3} {PO}_{3}$

(B) ${AgNO}_{3} \overset{Organic tissue (proteins)}{\to} Ag ↓ (black)$

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The yellow colour solution of ${Na}_{2} {CrO}_{4}$ changes to orange-red on passing ${CO}_{2}$ gas due to the formation of :

${CrO}_{5}$

${CrO}_{3}$

${Na}_{2} {Cr}_{2} O_{7}$

${Cr}_{2} O_{3}$

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Explanation

(C) ${CO}_{2} + H_{2} O \overset{}{\to} H_{2} {CO}_{3} ⇌ 2 H^{+} + {CO}_{4}^{2 -}; {CrO}_{4}^{2 -} + 2 H^{+} ⇌ {Cr}_{2} O_{7}^{2 -} (orange red) + H_{2} O$

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Yes. You can attempt every Chemistry question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.