Chemistry MCQs for NEET — Practice Questions with Answers

III<II<I<IV                                         

III<IV<II<I

II<III<I<IV                                         

IV<I<II<III

 ${{\mathrm{VO}}_2}^{+}<{\mathrm{Cr}}_2{{\mathrm{O}}_7}^{2-}<{{\mathrm{MnO}}_4}^{-}$                           

 ${{\mathrm{VO}}_2}^{+}<{{\mathrm{MnO}}_4}^{-}<{\mathrm{Cr}}_2{{\mathrm{O}}_7}^{2-}$

 ${\mathrm{Cr}}_2{{\mathrm{O}}_7}^{2-}<{{\mathrm{VO}}_2}^{+}<{{\mathrm{MnO}}_4}^{-},$                           

 ${\mathrm{Cr}}_2{{\mathrm{O}}_7}^{2-}<{{\mathrm{MnO}}_4}^{-}<{{\mathrm{VO}}_2}^{+}$

 ${{\mathrm{MnO}}_4^{}}^{-}$                               

 ${\mathrm{Cr}}_2{\mathrm{O}}_7^{2-}$

 ${\mathrm{VO}}_4^{3-}$                                 

 ${\mathrm{FeO}}_4^{2-}$

Decomposes into ${\mathrm{FeCl}}_2 \mathrm{and} {\mathrm{Cl}}_2.$               

Decomposes into $\mathrm{Fe} \mathrm{and} {\mathrm{Cl}}_2.$

Sublimes go give liquid ${\mathrm{FeCl}}_3$                         

Sublimes to give gaseous dimmer ${\left({\mathrm{FeCl}}_3\right)}_2.$

Heating hydrated ferric chloride at a high temperature in a stream of air.

Heating metallic iron in a stream of dry chlorine gas.

Reaction of ferric oxide with HCl (aq).

Reaction of metallic iron with HCl (aq).

Both ${\mathrm{SO}}_2 \mathrm{and} {\mathrm{SO}}_3$                         

 ${\mathrm{SO}}_2 \mathrm{only}$

 ${\mathrm{SO}}_3 \mathrm{only}$                                       

 ${\mathrm{Fe}}_2{\left({\mathrm{SO}}_4\right)}_3 \mathrm{only}$

 ${\mathrm{FeCl}}_3, {\mathrm{CH}}_3\mathrm{OH} \mathrm{and} {\mathrm{CH}}_3{\mathrm{COCH}}_3$                       

 $\left({\mathrm{CH}}_3\mathrm{O}\right)\mathrm{Fe}, \mathrm{HCl} \mathrm{and} {\mathrm{H}}_2\mathrm{O}$

 ${\mathrm{FeCl}}_2, \mathrm{HCl} \mathrm{and} {\mathrm{CH}}_3{\mathrm{COCH}}_3$                             

 $\mathrm{Fe}{\left(\mathrm{OH}\right)}_3, {\mathrm{FeCl}}_3 \mathrm{and} {\mathrm{CH}}_3{\mathrm{COCH}}_3$

Evolved ${\mathrm{I}}_2$ is reduced                                     

 ${\mathrm{Cul}}_2$ is formed

 ${\mathrm{Na}}_2{\mathrm{S}}_2{\mathrm{O}}_3$ is oxides                                         

 ${\mathrm{Cu}}_2{\mathrm{l}}_2$ is formed.

 ${\mathrm{PH}}_3$ reduces ${\mathrm{AgNO}}_3$ to metallic Ag.

Organic tissues turn ${\mathrm{AgNO}}_3$ black by reducing it to Ag.

$\mathrm{AgCN}$is soluble in $\mathrm{KCN}$.

All are correct statements.

 ${\mathrm{CrO}}_5$                                         

 ${\mathrm{CrO}}_3$

 ${\mathrm{Na}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$                                 

 ${\mathrm{Cr}}_2{\mathrm{O}}_3$