Chemistry MCQs for NEET — Practice Questions with Answers

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Assertion : tris (ethane-1, 2-diamine) nickel(II) chloride is homoleptic outer orbital complex

Reason : The geometry of Ni in tris (ethane-1, 2-diamine) nickel(II) chloride is trigonal bipyramidal.

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Explanation

(C) Nien3Cl2 is paramagnetic with two unpaired electrons and has octahedral geometry with sp3d2

     hybridisation and as nd orbital participate in hybridisation it is outer orbital complex. As all ligands

     are as same type, the complex is termed as homoleptic.

Assertion : Bis(dimethylglyoximato)nickel(II) can show geometrical isomerism.

Reason : Tetrahedral complexes with chiral structure exhibit optical isomerism.

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Assertion : The magnitude of charge density for a given ligand increases as the charge on the metal

                  ion increases.

Reason : NH3 is a weak field ligand towards Co2+ but acts as a strong field ligand towards Co3+.

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Explanation

(B) As metal ion charge increases the ligands are drawn closer to the metal ion because of its increased

     charge density. As the ligands move closer, they cause greater splitting of the d-orbital, there by

     producing a large t2g value.

Addition of Br2 on cis-butene-2 gives:

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Explanation

Addition of Br2 on alkene is always anti addition

In SN2 reactions, the correct order of reactivity for the following compounds : CH3ClCH3CH2ClCH32CHCl and CH33CCl is :

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Explanation

(b) Due to more -I.E. of attached groups in CH33CCl or due to max crowding round central carbon atom favours SN l mechanism.

Cl2 Benzotrichloride Hydrolysis Y

X and Y respectievely are:

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Explanation

(c) C6H5CHCl2 C6H5CClHOH C6H5COOH

Benzene on reaction with a mixture of HNO3 and H2SO4 followed by reaction of Cl2/FeCl3 gives:

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In the following sequences of reactions;

CH3CH2CH2IKOH(alc.)(A)Br2(B)NaNH2/NH3(C)

the end product (C) is:

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Explanation

(c) CH3CH2CH2I-HIKOH(alc.)CH3CH=CH2Br2CH3CHBrCH2Br-2HBrNaNH2CH3CCH

Friedel-Craft's reaction of bromobenzene with methyl iodide gives:

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Explanation

(c) Bromo group, o- and p-directing.

Benzyl chloride (C6H5CH2Cl) can be prepared from toluene by chlorination with:

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