Chemistry MCQs for NEET — Practice Questions with Answers

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Carbolic acid is the name used for:

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Explanation

(b) C6H5OH is also called carbolic acid.

When phenol is reacted with chloroform and an alkali like NaOH, the compound formed is salicylaldehyde. If we use pyrene in place of chloroform the product obtained is:

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When phenol is treated with excess bromine water, it gives:

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Explanation

When phenol is treated with an excess of bromine water, it undergoes electrophilic substitution reaction, and the product formed is 2,4,6-tribromophenol. The bromine atoms substitute the hydrogen atoms present in the benzene ring of phenol.

In the reaction, Phenol DIstillationZn(A) Conc. HNO3 at 60°CConc. H2SO4(B) NaOH(aq)Zn(C)

The compounds (A),(B) and (C) are of the following:

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Explanation

(d) C6H5OH ZnC6H6HNO3H2SO4C6H5NO2 ZN+NaOH(aq)C6H5NH|C6H5NH

Resorcinol and conc. H2SO4 in presence of phthalic anhydride produce a compound which is:

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An organic compound C7H8O is neither soluble in NaOH nor gives blue colour with FeCl3, is:

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Explanation

(c) The given statement represents only ether.

Which of the following reagents may be used to distinguish between phenol and benzoic acid?

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Explanation

(d) Neutral FeCl3(aq) gives violet coloured complex with phenol.

An unknown alcohol is treated with the “Lucas reagent” to determine whether the alcohol is primary, secondary or tertiary. Which alcohol reacts the fastest and by what mechanism:

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Explanation

Propene,CH3-CH=CH2 can be converted into 1-propanol by oxidation.Which set of reagents among the following is ideal to effect the conversion? 

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Explanation

CH3-CH=CH2HydroborationBH3, THF(CH3CH2CH2)3BOH-H2O23CH3CH2CH2OH
                                       Tripropyl borane             Propan-1-ol

A compound with molecular formula C4H10O3 is converted by the action of acetyl chloride to a compound with molar mass 190. The original compound has: 

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Explanation

ROH + CH3COCl ------- ROCOCH3 + HCl 

    M                                   (M + 42)

 Acylation of each OH group results in an increase of molecular mass of 42. In the given problem molecular mass of the compound increases by 84 on acylation. Therefore, the compound has two OH groups.

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