Chemistry MCQs for NEET — Practice Questions with Answers

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Which can be reduced to corresponding hydrocarbon by Zn/HCl?

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Explanation

(a) Reduction of ketone to corresponding alkane using Zn/HCl is called Clemmensen reduction.

Nucleophilic addition reaction will be most favoured in                   [2006]

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Explanation

Formaldehyde (CH3CHO) has the smallest alkyl group (methyl) attached to the carbonyl carbon. This makes the carbonyl carbon more susceptible to nucleophilic addition due to less steric hindrance compared to other options, where larger alkyl groups are present.

The enolic form of acetone contains:

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In this reaction,

CH3CHO + HCN CH3CH(OH)CN H.OHCH3CH(OH)COOH

an asymmetric compound is generated. The acid obtained would be            

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Explanation

In the given reaction, an asymmetric carbon atom is generated when HCN adds to acetaldehyde (CH3CHO). The resulting product, 2-hydroxypropanoic acid (CH3CH(OH)COOH), exists as a racemic mixture containing equal amounts (50%) of the D and L isomers.

Which one of the following compounds on treatment with LiAlH4 will give a product that will give a positive iodoform test?

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Explanation

CH3COCH3 LiAlH4CH3CHOHCH3

This will give iodoform test.

Aldehydes and ketones will not form crystalline derivatives with                   

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Explanation

Dihydrogen sodium phosphate (NaH2PO4) does not react with aldehydes and ketones because NaH2POdoes not have any lone pair of electron on phosphorus atom, so it cannot act as a nucleophile.

Oxalic acid on treatment with conc. H2SO4 gives:

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Explanation

 H2C2O4 H2SO4 H2O +CO + CO2

Benzene sulphonic acid on treating with P2O5 gives:

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Explanation

When benzene sulfonic acid is treated with phosphorus pentoxide (P2O5), the sulfonic acid group (-SO3H) is dehydrated to form the corresponding benzene sulfonic acid anhydride or benzenesulfonyl anhydride.

The IUPAC name of crotonaldehyde is:

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Explanation

(b) Crotonaldehyde is CH3.CH=CH.CHO.

The IUPAC name of the CH3COCH(CH3)2 is:

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Explanation

The IUPAC name for CH3COCH(CH3)2 is 3-methyl-2-butanone. The longest carbon chain has 4 carbon atoms, with a ketone (CO) group at the 2nd position and a methyl (CH3) group at the 3rd position.

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