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Chemistry MCQs for NEET — Practice Questions with Answers

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NEET 2025

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Given below are two statements:

Statement I: A hypothetical diatomic molecule with bond order zero is quite stable.

Statement II: As bond order increases, the bond length increases.

In the light of the above statements, choose the most appropriate answer:

A. Both Statement I and Statement II are true B. Both Statement I and Statement II are false C. Statement I is true but Statement II is false D. Statement I is false but Statement II is true

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Explanation

Bond order zero means the molecule does not exist / is unstable (I false). Bond length decreases (not increases) with increasing bond order (II false).

NEET 2025

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Out of the following complex compounds, which of the compound will be having the minimum conductance in solution?

A. $[\text{Co(NH}_3)_3\text{Cl}_3]$ B. $[\text{Co(NH}_3)_4\text{Cl}_2]$ C. $[\text{Co(NH}_3)_6]\text{Cl}_3$ D. $[\text{Co(NH}_3)_5\text{Cl}]\text{Cl}$

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Explanation

$[\text{Co(NH}_3)_3\text{Cl}_3]$ is a non-electrolyte (no ions in solution), so it has the minimum conductance.

NEET 2025

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Match List-I with List-II:

List-I — A. $\text{XeO}_3$, B. $\text{XeF}_2$, C. $\text{XeOF}_4$, D. $\text{XeF}_6$

List-II — I. $sp^3d$; linear, II. $sp^3$; pyramidal, III. $sp^3d^3$; distorted octahedral, IV. $sp^3d^2$; square pyramidal

Choose the correct answer:

A. A-II, B-I, C-IV, D-III B. A-II, B-I, C-III, D-IV C. A-IV, B-II, C-III, D-I D. A-IV, B-II, C-I, D-III

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Explanation

$\text{XeO}_3$: $sp^3$ pyramidal (II); $\text{XeF}_2$: $sp^3d$ linear (I); $\text{XeOF}_4$: $sp^3d^2$ square pyramidal (IV); $\text{XeF}_6$: $sp^3d^3$ distorted octahedral (III).

NEET 2025

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$\text{C(s)} + 2\text{H}_2\text{(g)} \to \text{CH}_4\text{(g)}$; $\Delta H = -74.8\ \text{kJ mol}^{-1}$. Which of the following diagrams gives an accurate representation of the above reaction? [R → reactants; P → products]

A. No net change (R and P at same level) B. Endothermic (P above R) C. Exothermic, P below R by 74.8 D. Endothermic, P above R

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Explanation

$\Delta H$ is negative (exothermic), so the products lie below the reactants by 74.8 kJ mol⁻¹, with an activation hump in between.

NEET 2025

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Match List-I with List-II:

List-I (Example) — A. Humidity, B. Alloys, C. Amalgams, D. Smoke

List-II (Type of Solution) — I. Solid in solid, II. Liquid in gas, III. Solid in gas, IV. Liquid in solid

Choose the correct answer:

A. A-II, B-IV, C-I, D-III B. A-II, B-I, C-IV, D-III C. A-III, B-I, C-IV, D-II D. A-III, B-II, C-I, D-IV

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Explanation

Humidity = liquid in gas (II); Alloys = solid in solid (I); Amalgams = liquid (Hg) in solid (IV); Smoke = solid in gas (III).

NEET 2025

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The correct order of decreasing basic strength of the given amines is:

A. N-methylaniline > benzenamine > ethanamine > N-ethylethanamine B. N-ethylethanamine > ethanamine > benzenamine > N-methylaniline C. N-ethylethanamine > ethanamine > N-methylaniline > benzenamine D. benzenamine > ethanamine > N-methylaniline > N-ethylethanamine

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Explanation

Aliphatic amines are more basic than aromatic. Secondary (N-ethylethanamine) > primary aliphatic (ethanamine) > N-methylaniline > aniline (benzenamine).

NEET 2025

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Among the following, choose the ones with equal number of atoms. A. 212 g of $\text{Na}_2\text{CO}_3$ [molar mass 106 g], B. 248 g of $\text{Na}_2\text{O}$ [molar mass 62 g], C. 240 g of NaOH [molar mass 40 g], D. 12 g of $\text{H}_2$ [molar mass 2 g], E. 220 g of $\text{CO}_2$ [molar mass 44 g]. Choose the correct answer:

A. A, B, and C only B. A, B, and D only C. B, C, and D only D. B, D, and E only

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Explanation

A: 2 mol × 6 atoms = 12 $N_A$; B: 4 mol × 3 = 12 $N_A$; C: 6 mol × 3 = 18 $N_A$; D: 6 mol × 2 = 12 $N_A$; E: 5 mol × 3 = 15 $N_A$. Equal (12 $N_A$): A, B and D.

NEET 2025

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Match List I with List II:

List I (Name of Vitamin) — A. Vitamin B₁₂, B. Vitamin D, C. Vitamin B₂, D. Vitamin B₆

List II (Deficiency disease) — I. Cheilosis, II. Convulsions, III. Rickets, IV. Pernicious anaemia

Choose the correct answer:

A. A-I, B-III, C-II, D-IV B. A-IV, B-III, C-I, D-II C. A-II, B-III, C-I, D-IV D. A-IV, B-III, C-II, D-I

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Explanation

B₁₂ → Pernicious anaemia (IV); D → Rickets (III); B₂ → Cheilosis (I); B₆ → Convulsions (II).

NEET 2025

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The correct order of decreasing acidity of the following aliphatic acids is:

A. $(\text{CH}_3)_3\text{CCOOH} > (\text{CH}_3)_2\text{CHCOOH} > \text{CH}_3\text{COOH} > \text{HCOOH}$ B. $\text{CH}_3\text{COOH} > (\text{CH}_3)_2\text{CHCOOH} > (\text{CH}_3)_3\text{CCOOH} > \text{HCOOH}$ C. $\text{HCOOH} > \text{CH}_3\text{COOH} > (\text{CH}_3)_2\text{CHCOOH} > (\text{CH}_3)_3\text{CCOOH}$ D. $\text{HCOOH} > (\text{CH}_3)_3\text{CCOOH} > (\text{CH}_3)_2\text{CHCOOH} > \text{CH}_3\text{COOH}$

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Explanation

More alkyl (+I) groups decrease acidity. HCOOH (no alkyl) is strongest; the bulky $(\text{CH}_3)_3\text{CCOOH}$ is weakest.

NEET 2025

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Given below are two statements:

Statement I: Ferromagnetism is considered as an extreme form of paramagnetism.

Statement II: The number of unpaired electrons in a $\text{Cr}^{2+}$ ion (Z = 24) is the same as that of a $\text{Nd}^{3+}$ ion (Z = 60).

In the light of the above statements, choose the correct answer:

A. Both Statement I and Statement II are true B. Both Statement I and Statement II are false C. Statement I is true but Statement II is false D. Statement I is false but Statement II is true

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Explanation

Ferromagnetism is an extreme form of paramagnetism (I true). $\text{Cr}^{2+}$ ($3d^4$) has 4 unpaired electrons while $\text{Nd}^{3+}$ ($4f^3$) has 3 — not equal (II false).

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