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When ethene treated with $Br_2$ in presence of $CCl_4$ which compound is formed
$ CH_2 = CH_2 + Br_2 \xrightarrow [] {CCl_4} Br - CH_2 - CH_2-Br $
$ CH_3 CH_2 Cl \xrightarrow [KOH] {Alcoholic} A $ the product is
$ CH_3CH_2CI \xrightarrow [] { Alc.KOH} CH_2 = CH_2 + KCI + H_2O $ ($ \beta $ - Elimination reaction)
When butane 2-ol is heated with $H_2SO_4$ the major product is
When butane-2-ol is heated with concentrated $H_2SO_4$, it undergoes dehydration to form an alkene. The major product formed is But-2-ene (But-2-en) due to the formation of a more stable internal alkene compared to But-1-ene.
In following reaction what will be the major product $ CH_3CH = CH_2 + HCl \rightarrow Product $
The reaction of propene ($CH_3CH = CH_2$) with HCl follows Markovnikov's rule, where the hydrogen atom from HCl will add to the carbon with the greater number of hydrogen atoms, and the chlorine atom will add to the carbon with fewer hydrogen atoms. This results in the formation of 2-chloropropane ($CH_3CHClCH_3$) as the major product.
$CH_3CH = CH_2 + HBr \xrightarrow [] {Peroxide} give major product $
$ CH_3CH = CH_2 + HBr \xrightarrow [] {Peroxide } CH_3 - CH2 - CH2 - Br $ (Antimarkownikoff `s Rule)
Baeyer`s Test is used in the laboratory for
The disappearace of the purple colour of $KMnO_4$ in its reaction with an alkene is the test for unsaturation (double bond). is known as Baeyer`s Test.
Aqueous $H_2SO_4 $ reacts with 2-methyl-but-1-ene to give predominantly
Cyclopentene on treatment with alkaline $KMnO_4$ gives
Cyclopentene on treatment with alkaline $KMnO_4$ undergoes a syn addition reaction, resulting in the formation of a diol. Specifically, it forms Cis-1, 2-Cyclopentadiol. The reaction conditions favor syn addition, leading to the formation of cis diols.
Ethene with acidic $KMnO_4$ solution gives
$ CH_2 = CH_2 + 2 [ 0] \xrightarrow [Acidic] { KMnO_4} HCHO + HCHO $
The addition of HBr to pent-2-ene gives
The addition of HBr to pent-2-ene follows Markovnikov's rule, where the hydrogen atom from HBr attaches to the carbon with the greater number of hydrogen atoms, and the bromine attaches to the carbon with fewer hydrogen atoms. This results in a mixture of 2-bromo pentane and 3-bromo pentane.
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