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In the reaction $ C_2 H_5 - CH = CH_2 + HX \rightarrow product$ . What is the product
According to Markownikoffs Rules
The dehydrohalogenation of neopentyl bromide mainly gives
1,3-butadiene (Buta-1,3-diene) reacts with ethylene to form
A reagent used to test for unsataration of alkene is
$ CH_2 = CH_2 + Br_2 \rightarrow BrCH_2 - CH_2 + Br $ (Brown) (Colour less) Disappearance of brown colour is the test for unsaturation
The product obtained when Chloroform is heated with Silver powder is
$ 2CHCI_3 + 6 Ag \rightarrow HC \equiv CH + 6 AgCl $
What is the Chief product of reaction between Ethylidene dichloride and $alc. KOH / NaNH_2 $
$ CH_3 - CHCl_2 + 2 alc. KOH \rightarrow HC \equiv CH + 2KCl + 2 H_2O $
Ethylene dibromide on heating with alc.KOH gives mainly.
Ethylene dibromide (1,2-dibromoethane) on heating with alcoholic KOH undergoes dehydrohalogenation to form acetylene (C2H2). The reaction involves the elimination of two molecules of HBr, resulting in the formation of a triple bond.
Propyne is formed by reaction of
Propyne ($CH_3C≡CH$) is formed by the reaction of $CH_3Br$ (methyl bromide) with sodium acetylide ($NaC≡CH$). The sodium acetylide acts as a nucleophile and displaces the bromine atom from the methyl bromide, forming propyne.
The gas which gives Benzene on passing through a red hot iron tube is
When acetylene ($C_2H_2$) is passed through a red hot iron tube, it undergoes a trimerization reaction to form benzene ($C_6H_6$). This is a well-known industrial process for producing benzene.
In presence of nickel cyanide, acetylene gives
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