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Chemistry MCQs for NEET — Practice Questions with Answers

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Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: "Gabriel Synthesis is used in the preparation of primary alifatic amines." Statement - 2: "Primary aromatic amine can be prepared by Gabriel synthesis's method."

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Explanation

Gabriel Synthesis is specifically used for the synthesis of primary aliphatic amines and not for aromatic amines. Therefore, Statement - 1 is True and Statement - 2 is False.

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Each question given below contains statement - 1 (Assertion) and Statement - 2 (Reason). Each queastion has 4 choices (1), (2), (3) and (4). out of which only one is correct choose the correct option as under : Statement - 1: " The boiling points of alkylisocyanides are lower than their isomeric alkyl cyanides." Statement - 2: "Isocyanide group is polar, so its boiling points is higher than their isomeric alkyl cyanides."

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An organic compound (A) on reduction gives compound (B) on treatment with $CHCl_3$ and alcoholic KOH gives (C) on Catalytic reduction gives N - Methyl aniline. The compound (A) is........

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Explanation

The compound (A) is Nitrobenzene which upon reduction gives Aniline (B). When treated with $CHCl_3$ and alcoholic KOH, it forms Phenyl isocyanide (C). On catalytic reduction, Phenyl isocyanide forms N-Methyl aniline. Hence, the correct answer is Nitrobenzene.

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Which is formed when $(CH_3)_4 – N – OH$ is heated ?

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Explanation

$ (CH_3)_4.N. OH \xrightarrow [{}] { { \triangle } } [ (CH_3)_3N ]+ CH_3 OH $

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Which of the following reactant produced Benzanilide when it treated with aniline ?

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Explanation

Benzanilide is formed when aniline reacts with benzoyl chloride. The reaction is an example of Schotten-Baumann reaction, where an amine reacts with an acyl chloride to form an amide. The equation for the reaction is:

$$ ext{C}_6 ext{H}_5 ext{NH}_2 + ext{C}_6 ext{H}_5 ext{COCl} ightarrow ext{C}_6 ext{H}_5 ext{NHCOC}_6 ext{H}_5 + ext{HCl} $$

Here, benzoyl chloride (C$_6$H$_5$COCl) is the reactant that produces benzanilide when treated with aniline.

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Which of the following is the strongest base in aqueous solution ?

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Explanation

Dimethylamine is the strongest base in aqueous solution among the given options. This is because dimethylamine has two electron-donating methyl groups, which increase the electron density on the nitrogen atom, making it more willing to donate its lone pair of electrons. The order of basicity for amines generally follows:

$$ ext{Dimethylamine} > ext{Methylamine} > ext{Trimethylamine} > ext{Aniline} $$

Hence, dimethylamine (CH$_3$)$_2$NH is the strongest base.

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How many primary amines are possibile with the formula of $C_4 H_{11} N $ ?

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Explanation

Four (n - butylamine, isobutylamine, sec-butylamine, ter-butylamine)

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Which of the following is not the correct reaction of aryldiazonium salts ?

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Explanation

The reaction given in option o3 is not correct. Aryldiazonium salts react with hypophosphorous acid (H$_3$PO$_2$) to give the corresponding aryl compound (benzene in this case), not an aryl phosphate. The correct reaction is:

$$ ext{C}_6 ext{H}_5 ext{N}_2^+ ext{Cl}^- + ext{H}_3 ext{PO}_2 ightarrow ext{C}_6 ext{H}_6 + ext{N}_2 + ext{HCl} $$

Therefore, option o3 is the incorrect reaction.

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Gas evolved during the reaction of Na-metal on $ C_2H_5NH_2 $ is :

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Explanation

$ 2C_2H_5NH_2 + 2Na \rightarrow 2C_2H_5 NHNa + H_2 $

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The action of nitrous acid on an aliphatic primary amine, gives :

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Explanation

$ R- NH_2 +HNO_2 \rightarrow R - OH + N_2 + H_2O $ Aliphatic amine Alcohol

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