The wave length corressponding to photon is $ 0.016 A ^\circ $ . Its K.E ………….J . $ ( h = 6.66 \times 10^{-34} SI , c = 3.0 \times 10^8 ms ^ {-1} ) $
$ Use K-E = { hc \over \lambda } $
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The wave length corressponding to photon is $ 0.016 A ^\circ $ . Its K.E ………….J . $ ( h = 6.66 \times 10^{-34} SI , c = 3.0 \times 10^8 ms ^ {-1} ) $
$ Use K-E = { hc \over \lambda } $
In electron microscope electron behave like ...............
In an electron microscope, electrons exhibit wave-like behavior. This wave nature of electrons allows the electron microscope to achieve very high resolution, as the wavelength of electrons is much shorter than that of visible light. This principle is based on the wave-particle duality of electrons described by quantum mechanics.
Photo electric effect is maximum in ...
Which experimental observation correctly account for the phenomenon?
The emission spectra of atoms, which consist of discrete lines, provided experimental evidence for the quantization of energy in atoms, as proposed by Niels Bohr's atomic model.
The maximum kinetic energy of photoelectron emitted from the surface of work function f due to incidence of light of frequency n is E. If the frequency of incident light is doubled, then maximum kinetic of emitted photon will be
The de-Broglie associated with an electron accelerated through a voltage of 900 V is:
In a photoelectric experiment using a metal of work function 1.8 eV, if the maximum kinetic energy of emitted electrons is 1.5eV, then the corresponding value to stopping potential is:
Electrons used in an electron microscope are accelerated by a voltage of 25 kV. If the accelerating voltage is reduced to 6.25 kV, the resolving power of the microscope would:
Resolving power ( R.P. )
By de-Broglie relation-
So. R.P.
So new R.P. =
When the light of wavelength is used in a photoelectric experiment, the maximum kinetic energy of emitted electrons is found to be K. What will the maximum kinetic energy of the photoelectrons when the light of wavelength is used instead of :
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