Dual Nature of Matter and Radiation MCQs for NEET — Physics Questions with Answers

Practice free Dual Nature of Matter and Radiation (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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The wave length corressponding to photon is $ 0.016 A ^\circ $ . Its K.E ………….J . $ ( h = 6.66 \times 10^{-34} SI , c = 3.0 \times 10^8 ms ^ {-1} ) $

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Explanation

$ Use K-E = { hc \over \lambda } $

In electron microscope electron behave like ...............

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Explanation

In an electron microscope, electrons exhibit wave-like behavior. This wave nature of electrons allows the electron microscope to achieve very high resolution, as the wavelength of electrons is much shorter than that of visible light. This principle is based on the wave-particle duality of electrons described by quantum mechanics.

Photo electric effect is maximum in ...

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Which experimental observation correctly account for the phenomenon?

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Explanation

The emission spectra of atoms, which consist of discrete lines, provided experimental evidence for the quantization of energy in atoms, as proposed by Niels Bohr's atomic model.

The maximum kinetic energy of photoelectron emitted from the surface of work function f due to incidence of light of frequency n is E. If the frequency of incident light is doubled, then maximum kinetic of emitted photon will be

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Explanation

KE = -ϕE = hn-fWhen the frequency is doubled;(K.E.)=2hn-f=2hn-2f+f        =2(hn-f)+f(K.E.)'=2E+f

The de-Broglie associated with an electron accelerated through a voltage of 900 V is:

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Explanation

λ = 150V = 150900 = 16 = 0.41 Ao

A 200W sodium street lamp emits yellow light of wavelength 0.60μm. Assuming it to be50% efficient, in converting electrical energy into light, the number of photons of yellowlight emitted per second is nearly equal to-

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Explanation

2P =nthcλ200 x 50100 =n1×6.6 x 10-34 x 3 x 1086 x 10-7n= 3 x 1020 per sec

In a photoelectric experiment using a metal of work function 1.8 eV, if the maximum kinetic energy of emitted electrons is 1.5eV, then the corresponding value to stopping potential is:

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Explanation

4Stopping potential = K.E.maxe = 1.5V

Electrons used in an electron microscope are accelerated by a voltage of 25 kV. If the accelerating voltage is reduced to 6.25 kV, the resolving power of the microscope would:

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Explanation

Resolving power ( R.P. ) 1λ

By de-Broglie relation-

λ = h2meV

So. R.P. V

So new R.P. = 12th of initial R.P.

When the light of wavelength λ is used in a photoelectric experiment, the maximum kinetic energy of emitted electrons is found to be K. What will the maximum kinetic energy of the photoelectrons when the light of wavelength λ2 is used instead of λ:

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Explanation

 

When wavelength λ is used:hcλ=K+ϕϕ=hcλ-KWhen wavelength λ2 is used:2hcλ=K'+ϕ=K'+hcλ-KK'=2hcλ-hcλ+K=hcλ+K=K+ϕ+K=2K+ϕK' is more than 2K.

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