Dual Nature of Matter and Radiation MCQs for NEET — Physics Questions with Answers

Practice free Dual Nature of Matter and Radiation (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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Photoelectric effect was successfully explained first by

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Explanation

Einstein explained the photoelectric effect successfully first.

The spectrum of radiation 1.0×1014 Hz is in the infrared region. The energy of one photon of this in joules will be

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Explanation

(b) E=hv=6.64×10-34×1.0×1014=6.62×10-20 J

A photo cell is receiving light from a source placed at a distance of 1 m. If the same source is to be placed at a distance of 2 m, then the ejected electron

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Explanation

(d) Number of ejected electrons ∝ (Intensity) ∝ 1Distance2
Therefore an increment of distance two times will reduce the number of ejected electrons to 14th of the previous one.

In a photoelectric experiment for 4000 Å incident radiation, the potential difference to stop the ejection is 2 V. If the incident light is changed to 3000 Å, then the potential required to stop the ejection of electrons will be

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Explanation

(d) According to Einstein's photoelectric equation

E=W0+KmaxV0=hce1λ-1λ0

Hence if λ decreases V0 increases.

Photocell is a device to: 

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Explanation

(b) Number of electrons can be measured which are directly proportional to the intensity of radiation

Stopping potential for photoelectrons 

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Explanation

Stopping potential = V0=Kmx.e=hν0e

It also depends on the nature of the material of the cathode.

The maximum wavelength of radiation that can produce photoelectric effect in a certain metal is 200 nm. The maximum kinetic energy acquired by electron due to radiation of wavelength 100 nm will be 

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Explanation

(b) KmaxeV=123751λA0-1λ0A0=1237511000-12000=6.2 eV

The minimum energy required to remove an electron is called 

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Explanation

The minimum energy required to remove an electron is called work fuction.

Assuming photoemission to take place, the factor by which the maximum velocity of the emitted photoelectrons changes when the wavelength of the incident radiation is increased four times, is 

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Explanation

(d) hcλ=W0+12mvmax2

Assuming W0 to be negligible in comparison to hcλ

i.e. vmax21λvmax1λ

(On increasing wavelength λ to 4λ , vmax becomes half).

If the work function of a metal is 'ϕ' and the frequency of the incident light is 'ν', there is no emission of photoelectron if

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Explanation

(a) For no emission of photoelectron, energy of incident light < Work function

hv<ϕv<ϕh

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