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Electromagnetic Waves MCQs for NEET — Physics Questions with Answers

Practice free Electromagnetic Waves (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

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X-rays and $γ$ -rays are both electromagnetic waves, which one of the following statements is true?

in general, X-rays have a larger wavelength than that of $γ$ -rays

X-rays have a smaller wavelength than that of $γ$ -rays

$γ$ -rays have smaller frequency than that of X-rays

wavelength and frequency of X-rays are both larger than those of $γ$ -rays.

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Explanation

In general, X-rays have a larger wavelength than that of $γ$ -rays.

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Which of the following are not electromagnetic waves?

cosmic rays

gamma rays

$β$ -rays

X-rays

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Explanation

$β$ -rays are beam are fast-moving electrons.

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The frequencies of X-rays, $γ$ -rays and ultraviolet rays are respectively a, b and c. Then :

a < b, b < c

a > b, b > c

a > b, b > a

a < b, b > c

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Explanation

$Frequency of γ - rays is more than both the frequencies of X - rays and ultrav i olet rays .$

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A plane electromagnetic wave of frequency 40 MHz travels in free space in the x-direction. At some point and at some instant, the electric field $\vec{E}$ has its maximum value of 750 N/C in y-direction. The wavelength of the wave is

3.5 m

5.5 m

7.5 m

9.5 m

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Explanation

$λ = \frac{C}{v} = \frac{3 \times 10^{8}}{40 \times 10^{6}} = 7.5 m$

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The waves used in telecommunication are

infrared

visible light

microwaves

ultraviolet rays

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Explanation

The waves that are used in communication are radio waves, microwaves, infrared radiation, and light. But in telecommunication microwaves are used.

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Statement I : Light can travel in vacuum but sound cannot do so.

Statement II : Light is an electromagnetic wave and sound is a mechanical wave.

If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I

If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I.

If Statement - I is true but Statement - II is false.

If Statement - I is false but Statement - II is ture.

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Explanation

Light is an electromagnetic wave and does not require any medium to travel while the sound is a mechanical wave and requires a medium to travel.

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$The sun radiates electromagnetic energy at the rate of 3.9 \times 10^{26} W . Its radius is 6.96 \times 10^{8} m . The intensity of sunlight (in W /) at the solar surface will be :$

$5.6 \times 10^{6}$

$6.4 \times 10^{7}$

$4.2 \times 10^{6}$

$4.2 \times 10^{7}$

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Explanation

$J = \frac{P}{A} = \frac{3.9 \times 10^{26}}{4 π (6.96 \times 10^{8})} = 6.4 \times 10^{7} \frac{W}{m^{2}}$

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The wave impedance of free space is

0 $Ω$

376.6 $Ω$

1883 $Ω$

3776 $Ω$

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Explanation

$W a v e i m p e d a n c e; z = \sqrt{\frac{μ_{0}}{ε_{0}}} = \sqrt{\frac{4 π \times 10^{- 7}}{8.85 \times 10^{- 12}}} = 376.6 Ω$

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The frequency 1057 MHz of radiation arising from two close energy levels in hydrogen belongs to

radio waves

infrared waves

micro waves

$γ$ -rays

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Explanation

$λ = \frac{c}{ν} = \frac{3 \times 10^{8}}{1057 \times 10^{6}} = 0.28 m = 28 c m \Rightarrow r a d i o w a v e s$

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The wave associated with 2.7 K(kelvin) belongs to

radio waves

micro waves

ultraviolet ways

infrared waves

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Explanation

$λ_{m} T = c o n s \tan t = 0.2896 c m K λ_{m} = \frac{0.2896}{2.7} = 0.10 c m = 1 m m \Rightarrow m i c r o w a v e s$

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