Optics MCQs for NEET — Physics Questions with Answers

Practice free Optics (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Language English हिंदी
Clear Register free for difficulty & keyword filters

The formula $ \frac{n_2}{v} - \frac{n_1}{u} = \frac{n_2 - n_1}{R} $ is applicable for image formation using:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The NCERT text explicitly states regarding this formula: 'It holds for any curved spherical surface.' (Page 233, after presenting Equation 9.16). This formula is foundational for understanding refraction at a single spherical interface before moving on to lens maker's formula which uses two such surfaces.

What happens to a plane wavefront when it passes through a thin convex lens, according to Huygens' principle?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

As described in NCERT Section 10.3.1 (Wave Optics) and depicted in Figure 10.7(b): 'In Fig. 10.7(b) we consider a plane wave incident on a thin convex lens; the central part of the incident plane wave traverses the thickest portion of the lens and is delayed the most. The emerging wavefront has a depression at the centre and therefore the wavefront becomes spherical and converges to the point F which is known as the focus.' This illustrates the application of Huygens' principle to lens behavior.

In the context of refraction at a spherical surface, what does $N_1$ in the term $n_1 \sin i$ represent?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

From the NCERT text, 'The rays are incident from a medium of refractive index $n_1$, to another of refractive index $n_2$.' (Section 9.5.1). Therefore, $n_1$ is the refractive index of the medium of incidence.

Consider a case where light travels from medium 1 to medium 2. If the speed of light in medium 2 ($v_2$) is less than the speed of light in medium 1 ($v_1$), what can be concluded about the angle of refraction ($r$) relative to the angle of incidence ($i$)?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The NCERT text (Wave Optics, page 259) states: 'From the above equation, we get the important result that if $r < i$ (i.e., if the ray bends toward the normal), the speed of the light wave in the second medium ($v_2$) will be less then the speed of the light wave in the first medium ($v_1$).' This is a direct consequence of Snell's law $n_1 \sin i = n_2 \sin r$ and $n = c/v$, which implies $ \frac{\sin i}{\sin r} = \frac{n_2}{n_1} = \frac{v_1}{v_2} $. If $v_2 < v_1$, then $ \frac{v_1}{v_2} > 1 $, so $ \frac{\sin i}{\sin r} > 1 $, which means $\sin i > \sin r$, and thus $i > r$ (for acute angles).

What is the primary characteristic of ray optics as used in the chapter 'Ray Optics and Optical Instruments'?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The introductory paragraph of Chapter 9 (Ray Optics and Optical Instruments) states: 'In this chapter, we consider the phenomena of reflection, refraction and dispersion of light, using the ray picture of light. Using the basic laws of reflection and refraction, we shall study the image formation by plane and spherical reflecting and refracting surfaces.' This clearly defines the scope and approach of ray optics.

In the derivation of the formula for refraction at a spherical surface, the term MN/OM represents which angle approximately, for small angles?

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The NCERT text explicitly states: 'We have, for small angles, $\tan \angle NOM = \frac{MN}{OM}$'. This is a direct application of the small angle approximation where $\tan \theta \approx \theta \approx \sin \theta$ and relating it to the sides of the right-angled triangle formed by the perpendicular from N to the principal axis.

A simple microscope is limited to a maximum magnification of approximately:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

According to the NCERT text, 'A simple microscope has a limited maximum magnification (≤ 9) for realistic focal lengths.'

In a compound microscope, the objective lens forms an image that is:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The NCERT states: 'The lens nearest the object, called the objective, forms a real, inverted, magnified image of the object.'

The eyepiece of a compound microscope functions essentially like a:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The NCERT states: 'This serves as the object for the second lens, the eyepiece, which functions essentially like a simple microscope or magnifier, produces the final image, which is enlarged and virtual.'

For a compound microscope, the final image formed is always:

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

The NCERT states: 'Clearly, the final image is inverted with respect to the original object.'

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Optics question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.