Practice free Thermal Properties of Matter (Physics) NEET multiple-choice questions online with instant answers and detailed explanations. No login required.
A balloon partially inflated in a cool room expands to full size when placed in warm water. This is an example of:
The context mentions: 'Similarly, in case of gases, a balloon partially inflated in a cool room may expand to full size when placed in warm water.' This describes the volume expansion of the air (a gas) inside the balloon.
The coefficient of linear expansion ($\alpha_l$) has units of:
The definition $\Delta l/l = \alpha_l \Delta T$ implies that $\alpha_l = (\Delta l/l) / \Delta T$. Since $\Delta l/l$ is dimensionless, the unit of $\alpha_l$ is the inverse of the unit of temperature change, which is $K^{-1}$ (or $^\circ C^{-1}$). The table also lists units as $10^{-5} K^{-1}$.
Which of the following materials typically has a higher value of coefficient of linear expansion?
The context states: 'Normally, metals expand more and have relatively high values of $\alpha_l$.' Table 10.1 confirms metals like Aluminium, Brass, Iron, Copper, Silver, Gold have higher values compared to Glass (pyrex) and Lead.
If a rectangular sheet of a solid material has a length 'a' and breadth 'b', and its temperature increases by $\Delta T$, the increase in length $\Delta a$ can be expressed as:
The example for area expansion shows that when the temperature increases by $\Delta T$, 'a' increases by $\Delta a = \alpha_l a \Delta T$ and 'b' increases by $\Delta b = \alpha_l b \Delta T$. This directly refers to linear expansion.
The phenomenon where a blacksmith heats an iron ring before fitting it on the rim of a wooden wheel of a horse cart is an application of:
The introduction section mentions: 'you will find out why blacksmiths heat the iron ring before fitting on the rim of a wooden wheel of a horse cart'. This is a classic application of thermal expansion, where the ring expands on heating, allowing it to fit, and then contracts on cooling, forming a tight fit.
Which of the following equations correctly represents the ideal gas law?
According to the NCERT text (Chapter: THERMAL_PROPERTIES_OF_MATTER, Section 10.4; Chapter: KINETIC_THEORY, Summary point 1), the ideal gas equation relating pressure (P), volume (V), and absolute temperature (T) is given by PV = µRT, where µ is the number of moles and R is the universal gas constant.
The universal gas constant (R) has a value of approximately:
The NCERT text (Chapter: THERMAL_PROPERTIES_OF_MATTER, Section 10.4, and Chapter: KINETIC_THEORY, Summary point 1) states that the universal gas constant R = 8.31 J molâ»Â¹ Kâ»Â¹.
Real gases behave most like ideal gases under which of the following conditions?
The NCERT text (Chapter: KINETIC_THEORY, Section 12.3 and Summary point 1) mentions, 'Real gases satisfy the ideal gas equation only approximately, more so at low pressures and high temperatures.' Also, 'At low pressures or high temperatures the molecules are far apart and molecular interactions are negligible. Without interactions the gas behaves like an ideal one.'
If the temperature of a given mass of gas is kept constant, what can be inferred about the product of its pressure and volume (PV)?
According to Boyle's Law, derived from the ideal gas equation (PV = constant if µ and T are fixed), if temperature is constant, the product of pressure and volume remains constant (Chapter: KINETIC_THEORY, Section 12.3).
For a fixed pressure, the volume of a gas is directly proportional to its absolute temperature. This statement describes:
The NCERT text (Chapter: KINETIC_THEORY, Section 12.3) states, 'if you fix P, Eq. (12.1) shows that V ∠T i.e., for a fixed pressure, the volume of a gas is proportional to its absolute temperature T (Charles’ law).'
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