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Waves MCQs for NEET — Physics Questions with Answers

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A man sets his watch by the sound of a siren placed at a distance 1 km away. If the velocity of sound is 330 m/s

His watch is set 3 sec. faster

His watch is set 3 sec. slower

His watch is set correctly

None of the above

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Explanation

$Time = \frac{Distance}{Velocity} = \frac{1000}{330} = 3 .03 s e c$ .

Sound will be heard after 3.03 sec. So his watch is set 3sec, slower.

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Velocity of sound in air is

Faster in dry air than in moist air

Directly proportional to pressure

Directly proportional to temperature

Independent of pressure of air

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Explanation

$v = \sqrt{\frac{γ P}{ρ}}$ ; as P changes, ρ also changes. Hence $\frac{P}{ρ}$ remains constant so speed remains constant.

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The frequency of a sound wave is n and its velocity is v. If the frequency is increased to 4n, the velocity of the wave will be

v/4

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Explanation

Velocity of sound is independent of frequency. Therefore it is same (v) for frequency n and 4n.

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The speed of a wave in a certain medium is 960 m/s. If 3600 waves pass over a certain point of the medium in 1 minute, the wavelength is :

2 metres

4 metres

8 metres

16 metres

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Explanation

$n = \frac{3600}{60} = 60$ Hz ⇒ $λ = \frac{v}{n} = \frac{960}{60} = 16 m$

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Speed of sound at constant temperature depends on :

Pressure

Density of gas

Above both

None of the above

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Explanation

Speed do sound, doesn’t depend up on pressure and density medium.

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Sound velocity is maximum in :

H₂

N₂

O₂

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Explanation

$v = \sqrt{\frac{γ R T}{M}}$ ⇒ $v \propto \frac{1}{\sqrt{M}}$ .

Since M is minimum for H₂ so sound velocity is maximum in H₂.

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The minimum distance of reflector surface from the source for listening the echo of sound is :

28 m

18 m

19 m

16.5 m

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Explanation

$2 d = v \times t$ , where v = velocity of sound = 332 m/s

t = Persistence of hearing = $\frac{1}{10} \sec$ .

⇒ $d = \frac{v \times t}{2} = \frac{332 \times \frac{1}{10}}{2} = 16 .5 m$

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The type of waves that can be propagated through solid is :

Transverse

Longitudinal

Both (1) and (2)

None of these

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Explanation

Since solid has both the properties (rigidity and elasticity).

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Velocity of sound in air

I. Increases with temperature

II. Decreases with temperature

III. Increase with pressure

IV. Is independent of pressure

V. Is independent of temperature

Choose the correct answer. [Kerala (Engg.) 2001]

Only I and II are true

Only I and III are true

Only II and III are true

Only I and IV are true

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Explanation

Speed of sound $v \propto \sqrt{T}$ and it is independent of pressure.

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If at same temperature and pressure, the densities for two diatomic gases are respectively d₁ and d₂, then the ratio of velocities of sound in these gases will be :

$\sqrt{\frac{d_{2}}{d_{1}}}$

$\sqrt{\frac{d_{1}}{d_{2}}}$

d₁d₂

$\sqrt{d_{1} d_{2}}$

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Explanation

Speed of sound $v = \sqrt{\frac{γ P}{d}}$ ⇒ $\frac{v_{1}}{v_{2}} = \sqrt{\frac{d_{2}}{d_{1}}}$ (âˆµ P - constant)

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