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Physics MCQs for NEET — Practice Questions with Answers

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Assertion – Reason type questions : For the following questions, statement as well as the reason(s) are given. Each questions has four options. Select the correct option. Statement – 1 : The periodic time of a stiff spring is less than that of a soft spring. Statement – 2 : The periodic time of a spring depends on its force constant value and for a stiff spring, it is more.

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Explanation

Energy dissipates & so amplitude decreases. Statement -2 in false.

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Assertion – Reason type questions : For the following questions, statement as well as the reason(s) are given. Each questions has four options. Select the correct option. Statement – 1 : The amplitude of an oscillator decreases with time. Statement – 2 : The frequency of an oscillator decreases with time.

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Explanation

Statement -1 in true. statement -2 in false. In a SHM, amplitude & phase does not depend on restoring force.

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Assertion – Reason type questions : For the following questions, statement as well as the reason(s) are given. Each questions has four options. Select the correct option. Statement – 1 : For a particle executing SHM, the amplitude and phase is decided by its initial position and initial velocity. Statement – 2 : In a SHM, the amplitude and phase is dependent on the restoring force.

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Explanation

Time taken bythe spring $k_2$ to get maximum compressed from point D= half period of oscillation of the block. (if block in attached at the force end of spring) $ i.e t_2 = { T_2 \over 2 } = { 1 \over 2 } 2 \pi \sqrt {m \over k_2 } = { 1 \over 2 } 2 \pi \sqrt {0.2 \over 0.3 } = { \pi \over 4 } s $

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A block having mass M is placed on a horizontal frictionless surface. This mass is attached to one end of a spring having force constant k. The other end of the spring is attached to a rigid wall. This system consisting of spring and mass M is executing SHM with amplitude A and frequency f. When the block is passing through the mid-point of its path of motion, a body of mass mis placed on top of it, as a result of which its amplitude and frequency changes to A’ and f’. The ratio of frequencies $ { f' \over f } $ =..............................

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Explanation

$ f = {1 \over 2 \pi } \sqrt { k \over M } $ and $ f' = {1 \over 2 \pi } \sqrt { k \over m + M } $

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A block having mass M is placed on a horizontal frictionless surface. This mass is attached to one end of a spring having force constant k. The other end of the spring is attached to a rigid wall. This system consisting of spring and mass M is executing SHM with amplitude A and frequency f. When the block is passing through the mid-point of its path of motion, a body of mass mis placed on top of it, as a result of which its amplitude and frequency changes to A’ and f’. If the velocity before putting the mass and after putting it is $ \nu $ and $ \nu ' $ respectively, then $ { \nu' \over \nu } $=...................................

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Explanation

According to the law of conservation of momentum, $ MV = (M + m) \nu ' $

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A block having mass M is placed on a horizontal frictionless surface. This mass is attached to one end of a spring having force constant k. The other end of the spring is attached to a rigid wall. This system consisting of spring and mass M is executing SHM with amplitude A and frequency f. When the block is passing through the mid-point of its path of motion, a body of mass mis placed on top of it, as a result of which its amplitude and frequency changes to A’ and f’. The ratio of amplitudes $ { A^1 \over A } $ = ........

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Explanation

According to the law of conservation of energy, Kinetic Energy at mid point = potential Energy at the end points $ \therefore { 1 \over 2 } M \nu^2 = { 1 \over 2 } k A^2 $ $ And { 1 \over 2} ( M + m ) \nu ^{1 ^2 } = {1 \over 2 } k A^{1 ^2 } $

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The equation for displacement of a particle at time t is given by the equation y = 3Cos2t + 4Sin2t. . The motion of the particle is …………..

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Explanation

$ y = 3 cos 2t + 4 sin 2 t $ $ \therefore A sin \phi = 3 and A cos \phi = 4 $ $ \therefore y = A sin \phi cos 2 t + A cos \phi sin 2 t $ $ \therefore y = A sin ( \omega t + \phi ) $ Which shows that the motion is simple harmonic motion

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The equation for displacement of a particle at time t is given by the equation y = 3Cos2t + 4Sin2t The periodic time of oscillation is ………

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Explanation

$ T = { 2 \pi \over \omega } = {2 \pi \over 2 } = \pi s $

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The equation for displacement of a particle at time t is given by the equation y = 3Cos2t + 4Sin2t. . The amplitude of oscillation is ……cm

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Explanation

$ amplitude A = \sqrt { 3^2 + 4^2 } = 5 cm $

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The equation for displacement of a particle at time t is given by the equation y = 3Cos2t + 4Sin2t. . The maximum acceleration of the particle is…………cm / s2.

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Explanation

Maximum Accelaration of $ A particle = A \omega^2 = 5 (2)^2 = 20 cms^{-2} $

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