Physics MCQs for NEET — Practice Questions with Answers

Practice free Physics NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology
Register free to filter questions

Two forks A and B when sounded together produce 4 beats/s. The fork A is in unison with 30 cm length of a sonometer wire and B is in unison with 25 cm length of the same wire at the same tension. The frequencies of the fork are

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ { f_2 \over f_1 } = { l_2 \over l_1 } = { 25 \over 30 } = { 5 \over 6 } $ $ f_2 - f_1 = 4 on solving we get f_2 = 24 Hz $ $ \therefore f_1 = 20 Hz $

A tuning fork of frequency 200 hz is in unison with a sonometer wire. The number of beats heard per second when the tension is increased by 1 % is

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ { f_2 \over f_1 } = \sqrt { 101 \over 100 } = \left( 1 + { 1 \over 100 } \right) ^ {1 /2 } = 1 + {1 /200} $ $ \therefore f_2 = f_1 + { f_1 \over 200} $ $ \therefore numbers of be ab s^{-1} = f_2 -f_1 = {f_1 \over 200} = 1 $

A bus is moving with a velocity of 5 m/s towards a huge wall. The driver sounds a horn of frequency 165 hz. If the speed of sound in air is 335 m/s, the number of beats heard per second by the passengers in the bus will be …….

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ { f_L \over f_S} = { \nu + \nu_L \over \nu + \nu_S } $ $ here \nu_L = + 5 ms^{-1} , \nu_s = -5 ms^{-1} , f_s = 165 Hz $ $ \therefore f_L =170 Hz \therefore Number of be ab s^{-1} = 170 -165 = 5 $

A vehicle with a horn of frequency n is moving with a velocity of 30 m/s in a direction perpendicular to the straight line joining the observer and the vehicle. The observer perceives the sound to havea frequency $( n + n_1 )$. If the sound velocity in air is 300 m/s, then

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

As the source is moving perpendicular to straight line joining the observer and source, (as if moving along a circle), apparent frequency is not affected $n_1 = 0$

A sonometer wire supports a 4 kg load and vibrates in fundamental mode with a tuning fork of frequency 416 hz. The length of the wire between the bridges is now doubled. In order to maintain fundamental mode, the load should be changed to …….

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

At a displacement antinode, a pressure node is present. Since pressure does not change at its node, nor does density.

In brass, the velocity of a longitudinal wave is 100 times the velocity of a transverse wave. If $ Y = 1 \times 10^{11} N/m^2$, then stress in the wire is …………

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

For a sonometer fundamental $ f = {1 \over 22} \sqrt { T \over \mu } $ To maintain the fundamental mode, in doubling the length, tension must be quadrupled

A car blowing its horn at 480 hz moves towards a high wall at a speed of 20 m/s. If the speed of sound is 340 m/s, the frequency of the reflected sound heard by the driver sitting in the car will be closest to hz.

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

If the length of the wire between the two bridges is l , then the frequency of vibration is $ n = { 1 \over 21 } \sqrt { T \over m } = { 1 \over 21 } \sqrt { T \over \pi r^2 d $ If the length and diameter of the wire are doubled keeping the tension same, then new fundamental frequency will be n/4

A cylindrical tube open at both ends has a fundamental frequency f in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now………

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ {f_L \over f_S } = { \nu + \nu_L \over \nu + \nu_S } $ using this equation the frequency of reflected sound heard by the girl, $ f_L = { \nu + \nu_L \over \nu -\nu_S} f_S $

Three sound waves of equal amplitudes have frequencies (v-1 ), v, ( v+1). They superpose to give beats. The number of beats produced per second will be …….

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

$ f_{open} = { \nu \over 2l_ {open} } $ $ f_{closed } = { \nu \over 4 l_{closed} = { \nu \over 4l_{open} /2 } $ $ [ As l_{closed} = { l_{open} \over 2 } ]$ $ = {\nu \over 2 l_{open} = f_{open} $ i.e. frequency remains unchanged.

A wave travelling along the x-axis is described by the equation y(x,t) = 0.005Cos(áx - ât). If the wavelength and the time period of the wave are 0.08 m and 2.0 s respectively, then á and â in appropriate units are ………

You've reached today's free limit of 20 questions. Log in to keep practising for free.
Explanation

If we assume that all the three waves are in same phase at t = 0, we shall hear only 1 beat $s^{-1}$

Ready to ace NEET?

Free access · No credit card required

Frequently Asked Questions

Yes. You can attempt every Physics question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.