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Physics MCQs for NEET — Practice Questions with Answers

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A wire elongates by 1 mm when a load W is hanged from it. If the wire goes ever a pulley and two weight W each are hang at the two ends. What will be the elongation of the wire ? (in mm)

A. 2 l B. Zero C. l/ 2 D. l

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Explanation

Elongation in the wire l = TL /AY $ \therefore Elongation in wire tension in the wire in first case T_1 = wand in second case $ $ T_2 = { 2W \over W + W } = W $ As Tension in the wire in both the cases are equal. $ \therefore Elongation in the wire will be equal.$

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200 kg weight hanged at a free edge of vertical wire of length 600.5 cm when removed the weight, length reduced by 0.5 cm and it gets original status then what is the young modulus of wire ?

A. $ 2.35 \times 10 ^ {12} N/m^2 $ B. $ 1.35 \times 10 ^ {10 } N/m^2 $ C. $ 13.5 \times 10 ^ {11} N/m^2 $ D. $ 23.5 \times 10 ^ 9 N/m^2 $

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Explanation

Y = FA / Al

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The ratio of diameter of two wires of same material is n : 1 the length of wires are 4 m each. On applying the same load. What will be the increase in length of their wire ?

A. $ n^2 times $ B. n times C. 2n times D. None of the above

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Explanation

$ l \alpha { F \over r^2 y } \Rightarrow l \alpha { 1 \over r^2 } $ ( F,Land Y are constant )

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A steel wire is stretched with a definite load of If the young's modulus of the wire is Y. For decreasing the value of Y............

A. Radius is to be decreased B. Radius is to be increased C. Length is to be increased D. None of the above

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Explanation

It is the specific property of a particular material at a given temperature which can be changed only by temperature variations.

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The area of cross-section of a steel wire is $ ( Y = 2 \times 10^{11} N /m^2 ) $ is $ 0.1 cm^2 $ , what will be the force required to double its length ?

A. $ 2 \times 10 ^ {11} N $ B. $ 2 \times 10 ^ {11} N $ C. $ 2 \times 10 ^{10} N $ D. $ 2 \times 10 ^{6} N $

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Explanation

When the length of wire is doubled then l = L and strain = 1 $ \therefore Y = strain = F / A $

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Two wires A & B are of same materials. Their lengths in the ratio 1 : 2 and diameters are in the ratio 2 : 1 when stretched by force $ F_A and F_B $ respectively, they get equal increase in lengths . Then the ratio $ { FA \over FB } $ should be ....

A. 1:2 B. 1:1 C. 2:1 D. 8:1

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Explanation

$ F = Y \times A \times {l \over L } \Rightarrow F \alpha { r^2 \over L } $ ( y and L are constant )

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The mean distance between the atoms of iron is $ 3 \times 10 ^ {-10} $ and interatomic force constant for iron is 7 N /m . What is the young's modulus of elasticity for iron ?

A. $ 2.33 \times 10 ^ {5} N /m^2 $ B. $ 23.3 \times 10 ^ {10} N /m^2 $ C. $ 233 \times 10 ^ {10} N /m^2 $ D. $ 2.33 \times 10 ^ {10 } N /m^2 $

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Explanation

$ Y = { r \over r_0} = { 7 \over 3 \times 10^{-10 } } $

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A force of 200 N is applied at one end of a wire of length 2 m and having area of cross-section $ 10 ^ {-2} cm^2 $ , the other end of the wire is rigidly fixed. If of linear expansion of the wire $ \alpha = 8 \times 10 ^ {-6} / ^\circ C $ and young's modulus $ Y = 2.2 \times 10^{11} N/m^2 $ and its temperature is increased by $ 5 ^\circ C $ then the increase in the tension of the wire will be..........

A. 4.2 N B. 4.4N C. 2.4 N D. 8. 8 N

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Explanation

$ Increase in tension of wire = YA \alpha \triangle Q $

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A uniform plank of young's modulus Y is moved over a smooth horizontal surface by a constant horizontal force F, The area of cross-section of the plank is A. What is the compressive strain on its plank in the direction by the force ?

A. F /AY B. 2F /AY C. $ {1 \over 2 } \left( { F \over AY } \right) $ D. 3F /AY

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Explanation

$ Y = { { F \over A } \over strain } \Rightarrow strain = { F \over AY } $

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A rubber cord catapult has cross-sectional area $ 25 mm^2 $ and initial length of cord is 10 cm. It is stretched to 5 cm and then released to project a missile of mass 5 gm. Taking $ Y_{rubber} = 5 \times 10^8 N/m^2 $ velocity of projected missile is ..........

A. 20 m/s B. $ 100 m/s^{-1} $ C. $ 250 m/s^{-1} $ D. $ 200 m/s^{-1} $

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Explanation

Potential energy stored in the rubber cord calapult will be covered into kinetic energy of mass $ {1 \over 2 } mv^2 = {1 \over 2} { YAL^2 \over L } $

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