Physics MCQs for NEET — Practice Questions with Answers

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If the ratio of specific heat of a gas at Consgant pressure to that at constant volume is $ \gamma $ , the Change in internal energy of the mass of gas, when the volume changes from V to 2V at Constant Pressure p, is

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Explanation

$ \triangle u = { P (V_2 - V_1) \over \gamma _1 } = { PV \over \gamma - 1 } $

The change in internal energy, when a gas is cooled from $ 927 ^\circ to 27 ^\circ C $

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Explanation

$ U \alpha T { u_1 \over u_2} = { T_1 \over T_2} $ $ \therefore { u_1 - u_2 \over u_2} = {T_1 - T_2 \over T_2} $

For hydrogen gas Cp - Cv = a and for oxygen gas Cp - Cv = b, The relation between a and b is given by

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Explanation

For all gases $ C_p - C_v = R $

In a thermodynamic process, pressure ofa fixed mass ofa gas is changed in such a manner that the gas release 20J of heat and 8J of work has done on the gas- If the inifial internal energy of the gas was 30j, then the final internal energy will be

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Explanation

$ \triangle Q = \triangle u + \triangle w $

If for a gas $ { Cp \over Cv } = 1.67 $ this gas is made up to molecules which are

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Explanation

$ { C_p \over C_v }= 1+ { 2 \over f} $

One mole of a monoatomic gas $ ( \gamma = 5 /3 ) $ is mixed with one mole ofA diatomic gas $ ( \gamma= 7/5 ) $ what will be value of $ \gamma $ for mixture ?

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Explanation

monoatomic gas cv = 3/2 R, diatomic gas cv = 5 /2 R, one mole of each gas is mixed $ C_v (mix) = {1 \over 2} \left[ { 3\over 2} R + { 5 \over 2} R \right] = 2R $ $C_p (mix) = R+ C_v $ =R + 2R = 3R $ r = { C_p mix \over C_v mix} = { 3R \over 2R } = 1.5 $

If du represents the increase in internal energy of a thesmodynamic system and dw the work done by the system, which of the following statement is true ?

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Explanation

dQ = du + dw

One mole of a monoatomic ideal gas is mixed with one mole of a diatomic ideal gas The molas specific heat of the micture at constant volume is ..........

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Explanation

$ C_v mix = { n_1 Cv_1 + n_2 Cv_2 \over n_1 + n_2 } $

One mole of a monoatomic gas is heate at a constant pressure of 1 atmosphere from 0k to 100 k. If the gas constant R = 8.32 J/mol k the change in internal energy of the gas is approximate ?

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Explanation

$ \triangle U = \gamma C_v \triangle T $

A monoatomic ideal gas, initially at temperature $T_1 $ is enclosed in a cylindes fitted witha frictionless piston. The gas is allowed to expand adiabatically to a temperature $T_2 $ by releasing the piston suddenly If $L_1$ and $L_2$ the lengths of the gas colum be fore and afters expansion respectively, then $ { T_1 \over T_2} $ is given by

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Explanation

TV = [an adiabatic process] $T_1 V_1 = T_2 V_2 $ $ {T_1 \over T_2 } = \left( { V_2 \over V_1 } \right) $

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