A gun fires a bullet of mass 40 g with a velocity of 50 m/s. Because of this the gun is pushed back with a velocity of 1 m/s. The mass of the gun is
$ m_G v_G = m_B v_B =0 $
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A gun fires a bullet of mass 40 g with a velocity of 50 m/s. Because of this the gun is pushed back with a velocity of 1 m/s. The mass of the gun is
$ m_G v_G = m_B v_B =0 $
The decreases in the potential energy of a ball of mass 25 kg which falls from
a height of 40 cm is
$ \triangle U = mgh $
If a man increase his speed by 2 m/s, his K.E. is doubled, the original speed of the man is
Initial kinetic energy, $ E = { 1 \over 2} mv^2 $ Final kinetic energy, $ 2E = { 1 \over 2} m (v+2)^2 $
The potential energy of a conservative system is given by $U(X) = (x^2-5x) J $. Then the equilibrium position is at....... (where x in m)
For a conservation field. Force, $ F = - { du \over dx} $ At equilibrium position, F = 0
A single conservative force F(x) acts on a 2.5 kg particle that moves along the x- axis. The potential energy U(x) is given by $ U(x) = (10 + (x - 4)^2) $ where x is in meter. At x = 6.0m the particle has kinetic energy of 20J. what is the mechanical energy of the system ?
$ P.E. at X = 6m is U = 10 + (6 - 4)^ 2 = 14 J$ $ \therefore Mechanical energy = K.E. + P.E. = 20 + 14 = 34 J$
A body initially at rest undergoes one dimensonal motion with constant acceleration. The power delivered to it at time t is proportional to.....
Power, P = Fv = mav
An electric motor develops 5KW of power. How much time will it take to lift a water of mass 100 kg to a height of 20 m ? $ ( g = 10 m/s^2 )$
Power, $ P = {mgh \over t } $
Bansi does a given amount of work in 30 sec. Jaimeen does the same amount of work... in 15 sec. The ratio of the output power of Bansi to the Jaimeen is....
Power, $ P \alpha { 1 \over t } $
A force of $ ( 2 \hat i+ 3 \hat j -\hat k ) N $ N acts on a body for 5 second, produces a displacement of $ ( 3 \hat i+5 \hat j + \hat k ) $ .What was the power used ?
$ P = { W \over t } $ $ P = { \vec F . \vec d \over t } $
If the force F is applied on a body and it moves with a velocity v, the power will be
Power = Work/ Time.
Work = Force x displacement
So, now Power = Force x displacement / Time.
But displacement / Time = velocity
According to the question, Force is F and V is velocity so,
Power = F x v
But power is a scalar quantity so, we have dot product for power so......
Power = Fv or F.v
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The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.