Physics MCQs for NEET — Practice Questions with Answers

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If pressure P, velocity V and time T are taken as fundamental physical quantities, the dimensional formula of force is  

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Explanation

Let F∝PxVyTz

by substituting the following dimensions : 

[P]=[ML−1T−2], [V]=[LT−1], [T]=[T]

and comparing the dimension of both sides

x=1, y=2, z=2, so F=PV2T2

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The physical quantity which has dimensional formula as that of EnergyMass×Lengthis 

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Explanation

Energymass×length=[ML2T−2][M] [L]=[LT−2]

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If energy (E), velocity (v) and force (F) be taken as fundamental quantity, then what are the dimensions of mass 

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Explanation

Let m∝ExvyFz

By substituting the following dimensions :

[E]=[ML2T−2], [v]=[LT−1], [F]=[MLT−2]

and by equating the both sides

x=1, y=−2, z=0. So [m]=[Ev−2] 

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Dimensions of luminous flux are 

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Explanation

ML2T−3

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A physcial quantity x depends on quantities y and z as follows: x = Ay + B tan Cz, where A, B and C are constants. Which of the following do not have the same dimensions 

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Explanation

x=Ay+B tanCz

From the dimensional homogenity

[x]=[Ay]=[B]⇒[xA]=[y]=[BA]

[Cz]=[M0L0T0]=Dimension less

x and B; C and Z−1;y and BAhave the same dimension but x and A have the different dimensions.

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Which of the following pair does not have similar dimensions  

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Explanation

Tension = [MLT−2], Surface Tension = [MT−2]  

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Out of the following which pair of quantities do not have same dimensions 

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Explanation

Torque = [ML2T−2], Moment of inertia = [ML2] 

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Identify the pair which has different dimensions 

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Explanation

Angular momentum = [ML2T−1], Frequency = [T−1]

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The dimensional formula M0L2T−2 stands for

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Explanation

Latent Heat L=Qm=Energymass=[ML2T−2][M]=[L2T−2] 

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Which of the following represents the dimensions of Farad 

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Explanation

C=QV=[AT][ML2T−3A−1]=[M−1L−2T4A2] 

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