Physics MCQs for NEET — Practice Questions with Answers

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If force (F), length (L) and time (T) are assumed to be fundamental units, then the dimensional formula of the mass will be

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Explanation

Let m=KFaLbTc

Substituting the dimension of

[F]=[MLT2], [C]=[L] and [T]=[T]

and comparing both sides, we get m=FL1T2

The dimensions of universal gas constant is

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Explanation

R=PVT=[ML1T2×L3θ]=[ML2T2θ1] 

In the relation y=acos(ωtkx), the dimensional formula for k is 

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Explanation

[Kx] = Dimension of ωt=(dimensionless) hence K=1X=1L=[L1]

[K]=[L1] 

Position of a body with acceleration 'a' is given by x=Kamtn,here t is time. Find dimension of m and n

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Explanation

As x=Kam×tn

[M0LT0]=[LT2]m[T]n=[LmT2m+n]

m = 1 and 2m+n=0 n=2.

"Pascal-Second" has dimension of 

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Explanation

NSm2=Nm2×S=Pascal-second. 

In a system of units if force (F), acceleration (A) and time (T) are taken as fundamental units then the dimensional formula of energy is 

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Explanation

E=KFaAbTc

[ML2T2]=[MLT2]a[LT2]b[T]c

[ML2T2]=[MaLa+bT2a2b+c]

a=1,a+b=2b=1

and 2a2b+c=2  c=2

E=KFAT2

The ratio of the dimension of Planck's constant and that of moment of inertia is the dimension of

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Explanation

hI=[ML2T1ML2]=[T1] 

Which of the following group have different dimension 

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Explanation

Dipole moment, electric flux, electric field

Out of following four dimensional quantities, which one quantity is to be called a dimensional constant 

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Explanation

The velocity of light in vacuum

Density of a liquid in CGS system is 0.625 g/cm3. What is its magnitude in SI system 

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Explanation

CGS SI

N1U1=N2U2

N1[M1L13]=N2[M2L23]

N2=N1[M1M2]×[L1L2]3=0.625[1g1kg]×[1cm1m]3

=0.625×103×106=625  

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