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Physics NEET Questions — Free MCQ Practice

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Assertion : In $y = A \sin (ω t - k x),$ $(ω t - k x)$ is dimensionless.

Reason : Because dimension of $ω = [M^{0} L^{0} T] .$

A. If both the assertion and the reason are true and the reason is a correct explanation of the assertion B. If both the assertion and reason are true but the reason is not a correct explanation of the assertion C. If the assertion is true but the reason is false D. If both the assertion and reason are false

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Explanation

As ω (angular velocity) has the dimension of $[T^{- 1}]$ not [T].

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Assertion : Radian is the unit of plane angle.

Reason : One radian is the angle subtended at the centre of a circle by an arc equal in length to the radius of the circle.

A. If both the assertion and the reason are true and the reason is a correct explanation of the assertion B. If both the assertion and reason are true but the reason is not a correct explanation of the assertion C. If the assertion is true but the reason is false D. If both the assertion and reason are false

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Explanation

Radian is the unit of plane angle.

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Assertion :In the relation $f = \frac{1}{2 l} \sqrt{\frac{T}{m},}$ where symbols have standard meaning, m represent linear mass density.

Reason : The frequency has the dimensions of inverse of time.

A. If both the assertion and the reason are true and the reason is a correct explanation of the assertion B. If both the assertion and reason are true but the reason is not a correct explanation of the assertion C. If the assertion is true but the reason is false D. If both the assertion and reason are false

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Explanation

From, $f = \frac{1}{2 l} \sqrt{\frac{T}{m}},$ $f^{2} = \frac{T}{4 l^{2} m}$

or, $m = \frac{T}{4 l^{2} f^{2}} = \frac{[M L T^{- 2}]}{L^{2} T^{- 2}} = \frac{M}{L} = \frac{M a s s}{l e n g t h}$ = linear mass density.

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The surface tension of a liquid is 70 dyne/cm. In MKS system its value is

A.

70 N/m

B.

7 × 10^–2 N/m

C.

7 × 10³ N/m

D.

7 × 10² N/m

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Explanation

1 dyne = 10^–5 Newton, 1 cm = 10^–2 m

$70 \frac{d y n e}{c m} = \frac{70 \times 10^{- 5}}{10^{- 2}} \frac{N}{m}$

= 7 × 10^–2 N/m.

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The SI unit of universal gas constant (R) is

A.

Watt K^–1 mol^–1

B.

Newton K^–1 mol^–1

C.

Joule K^–1 mol^–1

D.

Erg K^–1 mol^–1

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Explanation

$P V = n R T \Rightarrow R = \frac{P V}{n T} = \frac{J o u l e}{m o l e \times K e l v i n} = J K^{- 1} m o l^{- 1}$

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The unit of permittivity of free space $ε_{0}$ is

A.

Coulomb/Newton-metre

B.

Newton-metre²/Coulomb²

C.

Coulomb²/(Newton-metre)²

D.

Coulomb²/Newton-metre²

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Explanation

$F = \frac{1}{4 π ε_{0}} . \frac{Q_{1} Q_{2}}{r^{2}}$

$\Rightarrow ε_{0} \propto \frac{Q^{2}}{F \times r^{2}}$

So $ε_{0}$ has units of Coulomb²/Newton-m²

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The temperature of a body on Kelvin scale is found to be X K. When it is measured by a Fahrenheit thermometer, it is found to be X⁰F. Then X is

A.

301.25

B.

574.25

C.

313

D.

40

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Explanation

$\frac{F - 32}{9} = \frac{K - 273}{5} \Rightarrow \frac{x - 32}{9} = \frac{x - 273}{5} \Rightarrow x = 574 .25$

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What are the units of $K = 1 / 4 π ε_{0}$

A.

C²N^–1m^–2

B.

Nm²C^–2

C.

Nm²C²

D.

Unitless

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Explanation

Unit of $ε_{0} = C^{2} / N - m^{2}$

∴ Unit of K = Nm²C^–2

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The SI unit of surface tension is

A.

Dyne/cm

B.

Newton/cm

C.

Newton/metre

D.

Newton-metre

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Explanation

Newton/metre

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E, m, l and G denote energy, mass, angular momentum and gravitational constant respectively, then the dimension of $\frac{E l^{2}}{m^{5} G^{2}}$ are

A.

Angle

B.

Length

C.

Mass

D.

Time

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Explanation

$[E] = [M L^{2} T^{- 2}], [m] = [M], [l] = [M L^{2} T^{- 1}]$ and $[G] = [M^{- 1} L^{3} T^{- 2}]$ Substituting the dimension of above quantities in the given formula :

$\frac{E l^{2}}{m^{5} G^{2}}$ = $\frac{[M L^{2} T^{- 2}] {[M L^{2} T^{- 1}]}^{2}}{[M^{5}] {[M^{- 1} L^{3} T^{- 2}]}^{2}} = \frac{M^{3} L^{6} T^{- 4}}{M^{3} L^{6} T^{- 4}} = [M^{0} L^{0} T^{0}]$

Physics MCQs for NEET — Practice Questions with Answers

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