Blog Log in Get Started Free

Physics MCQs for NEET — Practice Questions with Answers

Practice free Physics NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology

Chapter Language Difficulty Show only questions I answered incorrectly Register free to filter questions

● ● ● ● ●

A man is 45 m behind the bus when the bus starts accelerating from rest with acceleration of 2.5 m/s². With what minimum velocity should the man start running to catch the bus?

12 m/s

14 m/s

15 m/s

16 m/s

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Let man will catch the bus after 't' sec . So he will cover distance ut.

Similarly distance travelled by the bus will be $\frac{1}{2} a t^{2}$ . For the given condition

$u t = 45 + \frac{1}{2} a t^{2} = 45 + 1 .25 t^{2}$ $[A s a = 2 .5 m / s^{2}]$

⇒ $u = \frac{45}{t} + 1 .25 t$

To find the minimum value of u

$\frac{d u}{d t} = 0$

so we get $t = 6 \sec$ then,

$u = \frac{45}{6} + 1 .25 \times 6 = 7 .5 + 7 .5 = 15 m / s$

● ● ● ● ●

A particle moves along x-axis as $x = 4 (t - 2) + a {(t - 2)}^{2}$ . Which of the following is true ?

The initial velocity of particle is 4

The acceleration of particle is 2a

The particle is at origin at t = 0

None of these

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$x = 4 (t - 2) + a {(t - 2)}^{2}$

At $t = 0, x = - 8 + 4 a = 4 a - 8$

$v = \frac{d x}{d t} = 4 + 2 a (t - 2)$

At $t = 0, v = 4 - 4 a = 4 (1 - a)$

But acceleration, $a = \frac{d^{2} x}{d t^{2}} = 2 a$

● ● ● ● ●

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5 sec is

9/25

3/5

25/9

1/25

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Distance covered in 5^th second,

$S_{5^{t h}} = u + \frac{a}{2} (2 n - 1) = 0 + \frac{a}{2} (2 \times 5 - 1) = \frac{9 a}{2}$

and distance covered in 5 second,

$S_{5} = u t + \frac{1}{2} a t^{2} = 0 + \frac{1}{2} \times a \times 25 = \frac{25 a}{2}$

∴ $\frac{S_{5^{t h}}}{S_{5}} = \frac{9}{25}$

● ● ● ● ●

What determines the nature of the path followed by the particle

Speed

Velocity

Acceleration

Both (2) and (3)

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

The nature of the path is decided by the direction of velocity, and the direction of acceleration. The trajectory can be a straight line, circle or a parabola depending on these factors.

● ● ● ● ●

Two trains, each 50 m long are travelling in opposite direction with velocity 10 m/s and 15 m/s. The time of crossing is

10 s

4 s

$2 \sqrt{3} s$

$4 \sqrt{3} s$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Time $= \frac{Total length}{Relative velocity} = \frac{50 + 50}{10 + 15} = \frac{100}{25} = 4 s e c$

● ● ● ● ●

A 120 m long train is moving in a direction with speed 20 m/s. A train B moving with 30 m/s in the opposite direction and 130 m long crosses the first train in a time

4 s

36 s

38 s

5 s

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Total distance $= 130 + 120 = 250 m$

Relative velocity $= 30 - (- 20) = 50 m / s$

Hence $t = 250 / 50 = 5 s$

● ● ● ● ●

A 210 meter long train is moving due North at a speed of 25m/s. A small bird is flying due South a little above the train with speed 5m/s. The time taken by the bird to cross the train is

6 s

7 s

9 s

10 s

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Relative velocity of bird w.r.t train $= 25 + 5 = 30 m / s$

time taken by the bird to cross the train $t = \frac{210}{30} = 7 s e c$

● ● ● ● ●

A police jeep is chasing with, velocity of 45 km/h a thief in another jeep moving with velocity 153 km/h. Police fires a bullet with muzzle velocity of 180 m/s. The velocity it will strike the car of the thief is

150 m/s

27 m/s

450 m/s

250 m/s

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Effective speed of the bullet

= speed of bullet + speed of police jeep

$= 180 m / s + 45 k m / h = (180 + 12 .5) m / s = 192 .5 m / s$

Speed of thief ’s jeep $= 153 k m / h = 42 .5 m / s$

Velocity of bullet w.r.t thief ’s car $= 192 .5 - 42 .5$ = 150m/s

● ● ● ● ●

A train of 150 meter length is going towards north direction at a speed of 10 m/sec. A parrot flies at the speed of 5 m/sec towards south direction parallel to the railway track. The time taken by the parrot to cross the train is

12 sec

8 sec

15 sec

10 sec

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

Relative velocity

$= 10 + 5 = 15 m / s e c$

∴ $t = \frac{150}{15} = 10 s e c$

● ● ● ● ●

A boat is moving with velocity of $3 \hat{i} + 4 \hat{j}$ in river and water is moving with a velocity of $- 3 \hat{i} - 4 \hat{j}$ with respect to ground. Relative velocity of boat with respect to water is :

$- 6 \hat{i} - 8 \hat{j}$

$6 \hat{i} + 8 \hat{j}$

$8 \hat{j}$

$6 \hat{i}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

The relative velocity of boat w.r.t. water

$= v_{b o a t} - v_{w a t e r} = (3 \hat{i} + 4 \hat{j}) - (- 3 \hat{i} - 4 \hat{j}) = 6 \hat{i} + 8 \hat{j}$

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every Physics question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.