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Physics MCQs for NEET — Practice Questions with Answers

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If no external force acts on the system, then the correct statement is:

velocity of centre of mass changes

momentum of centre of mass is conserved and constant

position of the center of mass changes with time

None of these

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Explanation

$F = \frac{dp}{dt}$

If F = 0, then p = constant and conserved

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The engine of a car produces acceleration 4 m/s² in the car. If this car pulls another car of same mass, what will be the acceleration produced

8 m/s²

2 m/s²

4 m/s²

$\frac{1}{2} m / s^{2}$

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Explanation

$F = m \times a$ , If force is constant then $a \propto \frac{1}{m}$ . So If mass is doubled then acceleration becomes half.

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A truck and a car are moving with equal velocity. If equal retarding force is applied on each, then on applying the brakes both will stop after certain distance

Truck will cover less distance before rest

Car will cover less distance before rest

Both will cover equal distance

None

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Explanation

F= ma

$a = \frac{F}{m}$

Stopping distance s = $\frac{v^{2}}{2 a} = \frac{m v^{2}}{2 F}$

If retarding force (F) and velocity (v) are equal then stopping distance ∝ m (mass of vehicle)

As $m_{car} < m_{truck}$ therefore car will cover less distance before coming to rest.

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A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250 m, the magnitude of the force is

3 N

3.5 N

4.0 N

4.5 N

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Explanation

$u = 0, S = 250 m, t = 10 \sec$

$S = u t + \frac{1}{2} a t^{2}$ ⇒ $250 = \frac{1}{2} a {[10]}^{2} \Rightarrow a = 5 m / s^{2}$

So, $F = m a = 0 .9 \times 5 = 4 .5 N$

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A cyclist turns around a curve at 15 miles/hour. If he turns at double the speed, the tendency to overturn is

Doubled

Quadrupled

Halved

Unchanged

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Explanation

$F = \frac{m v^{2}}{r}$ ⇒ $F \propto v^{2}$ . If v becomes double then F (tendency to overturn) will become four times.

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If the overbridge is concave instead of being convex, the thrust on the road at the lowest position will be

$m g + \frac{m v^{2}}{r}$

$m g - \frac{m v^{2}}{r}$

$\frac{m^{2} v^{2} g}{r}$

$\frac{v^{2} g}{r}$

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A car sometimes overturns while taking a turn. When it overturns, it is

The inner wheel which leaves the ground first

The outer wheel which leaves the ground first

Both the wheels leave the ground simultaneously

Either wheel leaves the ground first

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Explanation

Because the reaction on inner wheel decreases and becomes zero. So it leaves the ground first.

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A motor cyclist moving with a velocity of 72 km/hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 meters. The acceleration due to gravity is 10 m/sec². In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than

$θ = \tan^{- 1} 6$

$θ = \tan^{- 1} 2$

$θ = \tan^{- 1} 25 .92$

$θ = \tan^{- 1} 4$

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Explanation

$v = 72 k m / h o u r = 20 m / \sec$

$θ = \tan^{- 1} (\frac{v^{2}}{r g}) = \tan^{- 1} (\frac{20 \times 20}{20 \times 10}) = \tan^{- 1} (2)$

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A particle moves in a circular orbit under the action of a central attractive force inversely proportional to the distance ‘r’. The speed of the particle is

Proportional to r²

Independent of r

Proportional to r

Proportional to 1/r

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Explanation

$\frac{m v^{2}}{r} \propto \frac{K}{r}$ ⇒ v ∝ r°

i.e. speed of the particle is independent of r.

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Two masses M and m are attached to a vertical axis by weightless threads of combined length l. They are set in rotational motion in a horizontal plane about this axis with constant angular velocity ω. If the tensions in the threads are the same during motion, the distance of M from the axis is

$\frac{M l}{M + m}$

$\frac{m l}{M + m}$

$\frac{M + m}{M} l$

$\frac{M + m}{m} l$

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Explanation

When two masses M and m are rotating with the same angular velocity Ï‰ about a vertical axis, their centripetal accelerations must be equal. This means that M(Ï‰r)^2 = m(Ï‰(l-r))^2, where r is the distance of M from the axis. Solving this equation gives r = ml/(M+m).

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Frequently Asked Questions

Yes. You can attempt every Physics question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.