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Physics MCQs for NEET — Practice Questions with Answers

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A particle is moving with a constant speed along a straight line path. A force is not required to

Increase its speed

Decrease the momentum

Change the direction

Keep it moving with uniform velocity

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Explanation

Particle will move with uniform velocity due to inertia.

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Newton's second law gives the measure of

Acceleration

Force

Momentum

Angular momentum

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Explanation

$\vec{F} = m \vec{a}$

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A coin is dropped in a lift. It takes time t₁ to reach the floor when lift is stationary. It takes time t₂ when lift is moving up with constant acceleration. Then

t₁ > t₂

t₂ > t₁

t₁ = t₂

t₁ >> t₂

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Explanation

For stationary lift $t_{1} = \sqrt{\frac{2 h}{g}}$

and when the lift is moving up with constant acceleration $t_{2} = \sqrt{\frac{2 h}{g + a}} ∴ t_{1} > t_{2}$

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If the tension in the cable of 1000 kg elevator is 1000 kg weight, the elevator

Is accelerating upwards

Is accelerating downwards

May be at rest or accelerating

May be at rest or in uniform motion

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Explanation

Since T= mg, it implies that elevator may be at rest or in uniform motion.

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An object with a mass 10 kg moves at a constant velocity of 10 m/sec. A constant force then acts for 4 second on the object and gives it a speed of 2 m/sec in opposite direction. The acceleration produced in it, is

3 m/sec²

–3 m/sec²

0.3 m/sec²

–0.3 m/sec²

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Explanation

$\vec{a} = \frac{\vec{v_{2}} - \vec{v_{1}}}{t} = \frac{(- 2) - (+ 10)}{4} = \frac{- 12}{4} = - 3 m / s^{2}$

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The force acting on the object of mass 1 kg moving with acceleration $3 m / s^{2}$ is -

30 N

– 30 N

3 N

– 3 N

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Explanation

$F = m a = 1 \times (3) = 3 N$

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A machine gun is mounted on a 2000 kg car on a horizontal frictionless surface. At some instant the gun fires bullets of mass 10 gm with a velocity of 500 m/sec with respect to the car. The number of bullets fired per second is ten. The average thrust on the system is

550 N

50 N

250 N

250 dyne

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Explanation

u = velocity of bullet

$\frac{d m}{d t} =$ Mass thrown per second by the machine gun

= Mass of bullet × Number of bullet fired per second

$= 10 g \times 10 b u l l e t / \sec = 100 g / \sec = 0 .1 k g / \sec$

∴ Thrust $= \frac{u d m}{d t} = 500 \times 0 .1 = 50 N$

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A particle of mass 0.3 kg is subjected to a force F = –kx with k = 15 N/m. What will be its initial acceleration if it is released from a point 20 cm away from the origin

5 m/s²

10 m/s²

3 m/s²

15 m/s²

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Explanation

Force on particle at 20 cm away $F = k x$

F = 15 × 0.2 = 3 N $[As k = 15 N / m]$

∴ Acceleration = $\frac{Force}{Mass} = \frac{3}{0 .3} = 10 m / s^{2}$

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An elevator weighing 6000 kg is pulled upward by a cable with an acceleration of 5 ms^–2. Taking g to be 10 ms^–2, then the tension in the cable is

6000 N

9000 N

60000 N

90000 N

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Explanation

$T = m (g + a) = 6000 (10 + 5) = 90000 N$

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The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘a’ is 3 : 2. The value of ‘a’ is (g-Acceleration due to gravity of the earth)

$\frac{3}{2} g$

$\frac{g}{3}$

$\frac{2}{3} g$

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