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Physics MCQs for NEET — Practice Questions with Answers

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In free space, a rifle of mass M shoots a bullet of mass m at a stationary block of mass M at a distance D away from it. When the bullet has moved through a distance d towards the block, the centre of mass of the bullet - block system is at a distance of

$\frac{(D - d)}{M + m}$ from the bullet

$\frac{m d + M D}{M + m}$ from the block

$\frac{2 m d + M D}{M + m}$ from the block

$\frac{(D - d) M}{M + m}$ from the bullet

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Explanation

Distance between bullet and block at this instant is (D-d).

Distance from bullet = $\frac{M}{M + m} (D - d)$

And the distance from block = $\frac{m}{M + m} (D - d)$

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A wheel is at rest. Its angular velocity increases uniformly and becomes 80 rad/s after 5 s. The total angular displacement is

800 rad

400 rad

200 rad

100 rad

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Moment of inertia of an object does not depend upon

mass of object

mass distribution

angular velocity

axis of rotation

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Explanation

$I = \sum_{} {mr}^{2}$

$∴$ Moment of inertia depends upon mass distribution around axis and axis of rotation. It is independent of angular velocity $ω$ . Choice C is correct.

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A thin uniform circular disc of mass M and radius R is rotating in a horizontal plane about an axis passing through its center and perpendicular to its plane with an angular velocity $ω$ . Another disc of the same dimensions but of mass $\frac{1}{4} M$ is placed gently on the first disc co-axially. The angular velocity of the system is

$\frac{2}{3} ω$

$\frac{4}{5} ω$

$\frac{3}{4} ω$

$\frac{1}{3} ω$

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Explanation

$\begin{aligned} I_{1} ω_{1} & = I_{2} ω_{2} or ω_{2} = \frac{I_{1}}{I_{2}} ω_{1} \\ = \frac{(1 / 2 M R^{2})}{(1 / 2 M R^{2}) + \frac{1}{2} (1 / 4 M R^{2})} \\ = \frac{4}{5} ω \end{aligned}$

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When a ball of mass = 5kg hits a bat with a velocity = 3 m/s, in positive direction and it moves back with a velocity = 4 m/s, find the impulse in SI units

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When a torque acting upon a system is zero, then which of the following will be constant

force

Linear momentum

Angular momentum

Linear impulse

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Explanation

$(c) τ = \frac{dL}{dt}, if τ = 0 then L = constant$

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Consider a system of two particles having masses $m_{1} and m_{2}$ . If the particle of mass $m_{1}$ is pushed towards the center of mass of particles through a distance, by what distance would be the particle of the mass $m_{2}$ move so as to keep the center of mass of particles at the original position?

$\frac{m_{1}}{m_{1} + m_{2}} d$

$\frac{m_{1}}{m_{2}} d$

$\frac{m_{2}}{m_{1}} d$

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A wheel whose moment of inertia is 12 ${Kgm}^{2}$ has an initial angular velocity of 40 rad/sec. A constant torque of 20 Nm acts on the wheel. The time in which the wheel is accelerated to 100 rad/sec is

72 seconds

16 seconds

8 seconds

36 seconds

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Explanation

$\begin{aligned} τ = lα = \frac{l (ω - ω_{0})}{t}; 20 = \frac{12 (100 - 40)}{t} \\ t = 36 sec (Choice D) \end{aligned}$

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A flywheel is in the form of a uniform circular disc of radius 1 m and mass 2 kg. The work which must be done on it to increase its frequency of rotation from 5 rev $s^{- 1}$ to 10 rev $s^{- 1}$ is approximately

1.5 x $10^{2}$ J

3.0 x $10^{2}$ J

1.5 x $10^{3}$ J

3.0 x $10^{3}$ J

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Explanation

$W = change in rotational kinetic energy = \frac{1}{2} I (ω_{f}^{2} 9 - ω_{i}^{2}) \begin{aligned} = \frac{1}{2} (\frac{1}{2} {mR}^{2}) [{(2 {πf}_{f})}^{2} - {(2 {πf}_{i})}^{2}] \\ = \frac{1}{4} \times 2 \times (1)^{2} \times 4 \times π^{2} (100 - 25) \\ = 1 .48 \times 10^{3} J \approx 1 .5 \times 10^{3} J \end{aligned}$

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A particle of mass m has momentum p. it's kinetic energy will be

$p^{2} m$

$\frac{p^{2}}{m}$

$\frac{p^{2}}{2 m}$

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Explanation

$K = \frac{p^{2}}{2 m} and p = \sqrt{2}$ km are two standard results.

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