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Physics MCQs for NEET — Practice Questions with Answers

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Three-point masses, each of mass m are placed at the corners of an equilateral triangle of side a. The moment of inertia of this system ab5ut an axis along one Side of the triangle is

$3 {ma}^{2}$

${ma}^{2}$

${ma}^{2} \frac{3}{4}$

$\frac{3}{2} {ma}^{2}$

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Explanation

As the mass are point masses. The M.I. of masses lying on-axis is zero.

$∴ M . I . of the third mass abour one side as axis = m \times (\frac{\sqrt{3}}{2} a) = \frac{3 {ma}^{2}}{4}$

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A closed tube partly filled with water lies in a horizontal plane. If the tube is rotated about perpendicular bisector, the moment of inertia of the system

increases

decreases

remains constant

depends on sense of rotation

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Explanation

The mass tries to go away from the axis and, therefore, M.I. increases.

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A disc is rotating With an angular speed of m. If a child sits on it, which of the following is conserved?

kinetic energy

potential energy

linear momentum

angular momentum

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Explanation

According to the principle of conservation of angular momentum, when the child sits on the rotating disc, moment of inertia changes, so angular velocity also must change so as to keep angular momentum, as there is no torque acting on the system.

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The torque of a force -6 $\hat{i}$ acting at a point r = 4 $\hat{j}$ about origin will bee

-24 $\hat{k}$

24 $\hat{k}$

24 $\hat{j}$

24 $\hat{i}$

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Explanation

$τ = r \times F$

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A particle moves in a force field given by $\vec{F} = \hat{r} F (r)$ , where r is the unit vector along with the position vector $\vec{r}$ , then which is true?

The torque acting on the particle is not zero

The torque acting on the particle produces an angular acceleration in it

The angular momentum of the particle is conserved

The angular momentum of the particle increases.

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Explanation

$\begin{aligned} \vec{t} = \vec{r} \times \vec{F} & = \vec{r} \times \hat{r} F (r) = 0 \\ Therefore, \vec{t} & = \frac{\vec{dL}}{dt} = 0; \vec{L} = constant \end{aligned}$

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The ratio of rotational and translatory kinetic energies of the sphere is

2/9

2/7

2/5

7/2

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Explanation

$\frac{Rotational kinetic energy}{Translatory kinetic energy} = \frac{\frac{1}{2} {mv}^{2} \frac{K^{2}}{R^{2}}}{\frac{1}{2} {mv}^{2}} = \frac{K^{2}}{R^{2}} = \frac{2}{5}$

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Two perfectly elastic particles A and B of equal mass traveling along the line joining them with velocities 15 m/s and 10 m/s. After the collision, their velocities will be

10 m/s, 10 rn/s

15 m/s, 15 m/s

10 rn/s, 15 m/s

15 m/s, 10 m/s

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A small disc of radius 2 cm is cut from a disc of radius 6 cm. If the distance between their centres is 3.2 cm, what is the shift in the centre of mass of the disc?

0.4 cm

2.4 cm

1.8 cm

1.2 cm

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From a circular disc of radius R, a square is cut out with a radius as its diagonal. The centre of mass of remainder is at a distance (from the centre)

$\frac{R}{(4 π - 2)}$

$\frac{R}{2 π}$

$\frac{R}{(π - 2)}$

$\frac{R}{(2 π - 2)}$

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Two bodies with moment of inertia $I_{1} a n d I_{2}$ $(I_{1} > I_{2})$ and have equal angular momenta. If KE of rotation are $E_{1} a n d E_{2}$ , then

$E_{1} = E_{2}$

$E_{1} > E_{2}$

$E_{1} < E_{2}$

$E_{1} \geq E_{2}$

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Explanation

$E_{1} = \frac{1}{2} I_{1} ω_{1}^{2}, E_{2} = \frac{1}{2} I_{2} ω_{2}^{2} A s I_{1} ω_{1} = I_{2} ω_{2} I_{1}^{2} ω_{1}^{2} = I_{2}^{2} ω_{2}^{2}; I_{1} I_{1} ω_{1}^{2} = I_{2} I_{2} ω_{2}^{2} ∴ \frac{I_{1} ω_{1}^{2}}{I_{2} ω_{2}^{2}} = \frac{I_{2}}{I_{1}} o r \frac{\frac{1}{2} I_{1} ω_{1}^{2}}{\frac{1}{2} I_{2} ω_{2}^{2}} = \frac{E_{1}}{E_{2}} = \frac{I_{2}}{I_{1}} < 1 E_{1} < E_{2}$

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Frequently Asked Questions

Yes. You can attempt every Physics question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.