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Physics MCQs for NEET — Practice Questions with Answers

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A body of mass (m) is projected with velocity v₀ at an angle of projection $θ$ . The magnitude of angular momentum about origin after time t from projection is :

Increase with time

decrease with time

independent of time

none of these

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Explanation

$τ = m g u \cos θ t \frac{d L}{d t} = m g u \cos θ t L = m g u \frac{\cos θ t^{2}}{2}$

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A body of mass m slides down an incline and reaches the bottom with a velocity v. If the same mass were in the form of a ring which rolls down this incline, the velocity of the ring at bottom would have been

$\sqrt{2} v$

$(1 / \sqrt{2}) v$

$(\sqrt{2 / 5}) v$

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Explanation

$v' = \sqrt{\frac{2 g h}{1 + \frac{K^{2}}{R^{2}}}}, v = \sqrt{2 g h} v' = \sqrt{\frac{2 g h}{1 + 1}} = \frac{\sqrt{2 g h}}{\sqrt{2}} = \frac{v}{\sqrt{2}}$

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A 100 g iron ball having velocity 10 m/s collides with a wall at an angle 30° and rebounds with the same angle. If the period of contact between the ball and wall is 0.1 second, then the force experienced by the wall is

10 N

100 N

1.0 N

0.1 N

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A man fires a bullet of mass 200 g at a speed of 5 m/s. The gun is of one kg mass. By what velocity the gun rebounds backwards ?

0.1 m/s

10 m/s

1 m/s

0.01 m/s

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Explanation

$v_{G} = \frac{m_{B} v_{B}}{m_{G}} = \frac{0 .2 \times 5}{1} = 1 m / s$

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A body of mass M at rest explodes into three pieces, two of which of mass M/4 each are thrown off in perpendicular directions with velocities of 3 m/s and 4 m/s respectively. The third piece will be thrown off with a velocity of

1.5 m/s

2.0 m/s

2.5 m/s

3.0 m/s

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Explanation

Momentum of one piece $= \frac{M}{4} \times 3$

Momentum of the other piece $= \frac{M}{4} \times 4$

∴ Resultant momentum $= \sqrt{\frac{9 M^{2}}{16} + M^{2}} = \frac{5 M}{4}$

The third piece should also have the same momentum. Let its velocity be v, then

$\frac{5 M}{4} = \frac{M}{2} \times v$ or $v = \frac{5}{2} = 2 .5 m / s e c$

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A force of 50 dynes is acted on a body of mass 5 g which acts for an interval of 3 seconds, then impulse is

0.15 × 10^–3 N-s

0.98 × 10^–3 N-s

1.5 × 10^–3 N-s

2.5 × 10^–3 N-s

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Explanation

Impulse = Force × Time = 50 × 10^–5 × 3

= 1.5 × 10^–3 N-s

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In an explosion a body breaks up into two pieces of unequal masses. In this

Both parts will have numerically equal momentum

Lighter part will have more momentum

Heavier part will have more momentum

Both parts will have equal kinetic energy

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Explanation

Both part will have numerically equal momentum and lighter part will have more velocity.

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Two bodies of masses m₁ and m₂ have equal kinetic energies. If p₁ and p₂ are their respective momentum, then ratio p₁ : p₂ is equal to

$m_{1} : m_{2}$

$m_{2} : m_{1}$

$\sqrt{m_{1}} : \sqrt{m_{2}}$

$m_{1}^{2} : m_{2}^{2}$

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Explanation

$P = \sqrt{2 m E}$

∴ $P \propto \sqrt{m}$ $(if E = const.)$

∴ $\frac{P_{1}}{P_{2}} = \sqrt{\frac{m_{1}}{m_{2}}}$

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A light and a heavy body have equal momenta. Which one has greater K.E

The light body

The heavy body

The K.E. are equal

Data is incomplete

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Explanation

$E = \frac{P^{2}}{2 m}$ if P = constant then $E \propto \frac{1}{m}$

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If the momentum of a body is increased n times, its kinetic energy increases-

n times

2n times

$\sqrt{n}$ times

n² times

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Explanation

$E = \frac{P^{2}}{2 m}$ ∴ $E \propto P^{2}$

i.e. if P is increased n times then E will increase n² times.

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