Physics MCQs for NEET — Practice Questions with Answers

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If x longitudinal strain is produced in a wire of Young's modulus y, then energy stored in the material of the wire per unit volume is-

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Explanation

(d) Energy stored per unit volume =12×Stress×Strain

     =12×Young's modulus×Strain2=12×y×x2

The Young's modulus of a rubber string 8 cm long and density 1.5 kg/m3 is 5×108 N/m2, is suspended on the ceiling in a room. The increase in length due to its own weight will be

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Explanation

(b) l=L2dg2Y=8×10-222×5×108=9.6×10-11m

A and B are two wires of same material. The radius of A is twice that of B. They are stretched by the same load. Then the stress on B is

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Explanation

(b) 

Stress=forceArea  Stress1πr2SBSA=rArB2=22SB=4SA

If the length of a wire is reduced to half, then it can hold the ......... load

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Explanation

(b) Breaking force  Area of cross section of wire

i.e. load hold by the wire does not depend upon the length of the wire

Why the spring is made up of steel in comparison of copper

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Explanation

(c)

Springs are designed based on the property of elasticity. In the spring the restoring force develops due to deformation. This deformation depends on the elasticity of a material. In the given materials steel is more elastic than copper. So steel is preferred to manufacture a spring.

Steel and copper wires of same length are stretched by the same weight one after the other. Young's modulus of steel and copper are 2×1011N/m2 and 1.2×1011N/m2. The ratio of increase in length

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Explanation

(b)

 l=FLAYlsleu=YeuYs (F,L and Y are constant)       lsleu=1.2×10112×1011=35

The temperature of a wire of length 1 metre and area of cross-section 1cm2 is increased from 0°C to 100°C. If the rod is not allowed to increase in length, the force required will be α=10-5/°C and Y=1011N/m2

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Explanation

(b) F = force developed= YA αθ

    =1011×10-4×10-5×100=104N

The force constant of a wire does not depend on

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Explanation

(d) K=YAL=Y×πr2LKYr2L 

i.e. force constant of a wire depends on young's modules (nature of the material), radius of the wire and length of the wire.

The length of a wire is 1.0 m and the area of cross-section is 1.0×10-2cm2. If the work done for increase in length by 0.2 cm is 0.4 joule, then Young's modulus of the material of the wire is

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Explanation

(c) W=12YAδ2L0.4=12×Y×1-6×0.2×10-221      Y=2×1011N/m2

The quality of the material which opposes the change in shape, volume or length is called

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Explanation

(d)

Elasticity of a material resists change in shape, size, and volume of material.

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