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Physics MCQs for NEET — Practice Questions with Answers

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The pressure and temperature of two different gases are P and T having the volume V for each. They are mixed keeping the same volume and temperature, the pressure of the mixture will be- [Pb. PMT 1997, 98; DPMT 1999; MH CET 2003]

P/2

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Explanation

$μ_{1} = \frac{P V}{R T}, μ_{2} = \frac{P V}{R T} P' = \frac{(μ_{1} + μ_{2}) R T}{V} = \frac{2 P V}{R T} \times \frac{R T}{V} = 2 P$

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If the mean free path of atoms is doubled then the pressure of the gas will become: [RPMT 2000]

P/4

P/2

P/8

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Explanation

Mean free path, $λ \propto \frac{1}{P};$ If $λ$ is doubled then P becomes half.

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A diatomic molecule has how many degrees of freedom- [Pb. PET 2000]

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Explanation

A diatomic molecule has three translational and two rotational degrees of freedom.

Hence, total degrees of freedom f = 3 + 2 = 5

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A thermally insulated piston divides a container into two compartments. Volume, temperature, and pressure in the right compartment are 2V, T, and 2P, while in the left compartment the respective values are V, T, and P. If the piston can slide freely, then in the final equilibrium position, the volume of the right-hand compartment will be-

$\frac{3 V}{5}$

$\frac{9 V}{4}$

$\frac{12 V}{5}$

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Gas is found to obey the law $P^{2} V$ = constant. The initial temperature and volume are $T_{0}$ and $V_{0}$ . If the gas expands to a volume $3 V_{0}$ , its final temperature becomes:

$\frac{T_{0}}{3}$

$\frac{T_{0}}{\sqrt{3}}$

$3 T_{0}$

None of these

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Explanation

$P^{2} V$ = constant

$P = \frac{n R T}{V}$ or $P = \frac{C T}{V}$ (C=constant)

$∴ \frac{T^{2}}{V} = c o n s \tan t$

or $T \propto \sqrt{V}$

V is increased by 3 times.

Hence, T will increase by $\sqrt{3}$ times.

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For a gas, the r.m.s speed at 800 K is:

Four times the value at 200 K

Half the value at 200 K

Twice the value at 200 K

Same as at 200 K

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Explanation

$V_{r m s} = \sqrt{\frac{3 R T}{M}} ∴ V_{r m s} a t 800 K i s t w i c e t h a t a t 200 K .$

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The mean translational kinetic energy of a perfect gas molecule at the temperature T Kelvin is:

$\frac{1}{2} k T$

$\frac{3}{2} k T$

2 kT

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Explanation

Translational KE = $3 \times \frac{1}{2} k T$

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Choose the correct option related to the specific heat at constant volume $C_{V}$ -

$C_{V} = \frac{1}{2} f R$

$C_{V} = \frac{R}{γ - 1}$

$C_{V} = \frac{C_{P}}{γ}$

All of these

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Explanation

$C_{P} - C_{V} = R D i v i d i n g b y C_{V}, w e g e t γ - 1 = \frac{R}{C_{V}} ∴ C_{V} = \frac{R}{γ - 1} F u r t h e r U = \frac{f}{2} R T ∴ C_{V} = \frac{d U}{d T} = \frac{f}{2} R$

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Five molecules of a gas have speeds, 1, 2, 3, 4 and 5 km $s^{- 1}$ . The value of the root mean square speed of the gas molecules is:

3 km $s^{- 1}$

$\sqrt{11}$ km $s^{- 1}$

$\frac{1}{2} \sqrt{π}$ km $s^{- 1}$

3.5 km $s^{- 1}$

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Explanation

$V_{r m s} = \sqrt{\frac{1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2}}{5}} = \sqrt{\frac{55}{5}} = \sqrt{11} k m s^{- 1}$

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The average velocity of an ideal gas molecule is: [OJEE 2010]

proportional to $\sqrt{T}$

proportional to $T^{2}$

proportional to $T^{3}$

zero

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Explanation

The average velocity of an ideal gas molecule is zero.

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