Blog Log in Get Started Free

Physics MCQs for NEET — Practice Questions with Answers

Practice free Physics NEET multiple-choice questions online with instant answers and detailed explanations. No login required.

All Physics Chemistry Botany Zoology

Chapter Language Difficulty Show only questions I answered incorrectly Register free to filter questions

● ● ● ● ●

Three containers of the same volume contain three different gases. The masses of the molecules are $m_{1}, m_{2}$ and $m_{3}$ and the number of molecules in their respective containers are $N_{1}, N_{2}$ and $N_{3}$ . The gas pressure in the containers are $P_{1}, P_{2}$ and $P_{3}$ respectively. All the gases are now mixed and put in one of the containers. The pressure P of the mixture will be :

$P < (P_{1} + P_{2} + P_{3})$

$P = \frac{P_{1} + P_{2} + P_{3}}{3}$

$P = P_{1} + P_{2} + P_{3}$

$P > (P_{1} + P_{2} + P_{3})$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

3. According to Dalton’s law of partial pressures, the total pressure will be $P_{1} + P_{2} + P_{3}$ .

● ● ● ● ●

At a given volume and temperature, the pressure of a gas :

Varies inversely as its mass

Varies inversely as the square of its mass

Varies linearly as its mass

Is independent of its mass

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

3. $PV = mrT \Rightarrow P \propto m, (V, T \to constant)$

● ● ● ● ●

The rate of diffusion is :

Faster in solids than in liquids and gases

Faster in liquids than in solids and gases

Equal to solids, liquids, and gases

Faster in gases than in liquids and solids

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

4. It is because of their low densities.

● ● ● ● ●

Two thermally insulated vessels 1 and 2 are filled with air at temperatures $(T_{1}, T_{2}),$ volume $(V_{1}, V_{2})$ and pressure $(P_{1}, P_{2})$ respectively. If the valve joining the two vessels is opened, the temperature inside the vessel at equilibrium will be

$T_{1} + T_{2}$

$(T_{1} + T_{2}) / 2$

$\frac{T_{1} T_{2} (P_{1} V_{1} + P_{2} V_{2})}{P_{1} V_{1} T_{2} + P_{2} V_{2} T_{1}}$

$\frac{T_{1} T_{2} (P_{1} V_{1} + P_{2} V_{2})}{P_{1} V_{1} T_{2} + P_{2} V_{2} T_{2}}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

3. The number of moles of the system remains same,

$\frac{P_{1} V_{1}}{{RT}_{1}} + \frac{P_{2} V_{2}}{{RT}_{2}} = \frac{P (V_{1} + V_{2})}{RT} \Rightarrow T = \frac{P (V_{1} + V_{2}) T_{1} T_{2}}{(P_{1} V_{1} T_{2} + P_{2} V_{2} T_{1})}$

According to Boyle's law,

$P_{1} V_{1} + P_{2} V_{2} = P (V_{1} + V_{2}) ∴ T = \frac{(P_{1} V_{1} + P_{2} V_{2}) T_{1} T_{2}}{(P_{1} V_{1} T_{2} + P_{2} V_{2} T_{1})}$

● ● ● ● ●

For matter to exist simultaneously in gas and liquid phases :

The temperature must be 0 K.

The temperature must be less than $0 ° C$ .

The temperature must be less than the critical temperature.

The temperature must be less than the reduced temperature.

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

3. The temperature must be less than the critical temperature.

● ● ● ● ●

The value of critical temperature in terms of Vander Waal’s constant a and b is

$T_{c} = \frac{8 a}{27 Rb}$

$T_{c} = \frac{a}{2 Rb}$

$T_{c} = \frac{8}{27 Rb}$

$T_{c} = \frac{27 a}{8 Rb}$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

1. $T_{c} = \frac{8 a}{27 Rb}$

● ● ● ● ●

In Vander Waal’s equation, a and b represent $(P + \frac{a}{V^{2}}) (v - b) = RT$

Both a and b represent correction in volume

Both a and b represent adhesive force between molecules

a represents adhesive force between molecules and b correction in volume

a represents correction in volume and b represents adhesive force between molecules

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

3. In Vander Wall's equation, $(P + \frac{a}{V^{2}}) (V - b) = RT$ a represents intermolecular attractive force and b represents

volume correction.

● ● ● ● ●

At 0°C the density of a fixed mass of a gas divided by pressure is x. At 100°C, the ratio will be:

$x$

$\frac{273}{373} x$

$\frac{373}{273} x$

$\frac{100}{273} x$

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$2 . PV = μRT = \frac{m}{M} RT \Rightarrow \frac{m}{VP} = \frac{density}{P} = \frac{M}{RT} {(\frac{density}{P})}_{At 0 ° C} = \frac{M}{R (273)} = x . . . . . . . . . . (i) {(\frac{density}{P})}_{At 100 ° C} = \frac{M}{R (373)} . . . . . . . . . . (ii) \Rightarrow {(\frac{density}{P})}_{At 100 ° C} = \frac{273}{373} x$

● ● ● ● ●

At what temperature volume of an ideal gas at 0°C becomes triple :

546°C

182°C

819°C

646°C

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

$1 . At constant pressure V \propto T \Rightarrow \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}} \Rightarrow T_{2} = (\frac{V_{2}}{V_{1}}) T_{1} \Rightarrow T_{2} = (\frac{3 V}{V}) \times 273 = 819 K = 546 ° C$

● ● ● ● ●

If an ideal gas has volume V at 27°C and it is heated at a constant pressure so that its volume becomes 1.5V. Then the value of final temperature will be

600°C

177°C

817°C

None of these

You've reached today's free limit of 20 questions. Log in to keep practising for free.

Explanation

2. $T_{2} = (\frac{V_{2}}{V_{1}}) T_{1} = (\frac{1.5 V}{V}) \times (273 + 27) = 450 K \Rightarrow 177 ° C$

Ready to ace NEET?

Free access · No credit card required

Browse All Questions Create Free Account

Frequently Asked Questions

Yes. You can attempt every Physics question on this page for free without logging in, and check the correct answer with a detailed explanation instantly.

No account is required to attempt questions and view answers. A free account adds bookmarks, personal notes, and progress tracking.

The bank mixes NEET previous year questions (PYQs) with practice questions, each tagged with its exam appearances where applicable.