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Physics MCQs for NEET — Practice Questions with Answers

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Drift velocity v_d varies with the intensity of electric field as per the relation

$v_{d} \propto E$

$v_{d} \propto \frac{1}{E}$

v_d = constant

$v_{d} \propto E^{2}$

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Explanation

$v_{d} = \frac{e}{m} \times \frac{V}{l} τ$ or $v_{d} = \frac{e}{m} . \frac{E l}{l} τ$ (Since V = El)

$∴ v_{d} \propto E$

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In a conductor 4 coulombs of charge flows for 2 seconds. The value of electric current will be :

4 volts

4 amperes

2 amperes

2 volts

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Explanation

$i = \frac{q}{t} = \frac{4}{2} = 2 a m p e r e$

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When a piece of aluminum wire of finite length is drawn through a series of dies to reduce its diameter to half its original value, its resistance will become :

Two times

Four times

Eight times

Sixteen times

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Explanation

$V o l u m e o f w i r e i s c o n s \tan t . A_{i} L_{i} = A_{f} L_{f} π R^{2} L = π {(\frac{R}{2})}^{2} L' \Rightarrow L' = 4 L R' = ρ \frac{4 L}{π {(R / 2)}^{2}} = 16 ρ \frac{L}{π R^{2}} = 16 R$

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Through a semiconductor, an electric current is due to drift off:

Free electrons

Free electrons and holes

Positive and negative ions

Protons

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Explanation

In semiconductors charge carries are free electrons and holes.

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A metallic block has no potential difference applied across it, then the mean velocity of free electron is (T = absolute temperature of the block) :

Proportional to T

Proportional to $\sqrt{T}$

Zero

Finite but independent of temperature

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Explanation

In the absence of external electric field mean speed of free electron (V_r_ms) is given by $V_{r m s} = \sqrt{\frac{3 K T}{m}} \Rightarrow V_{r m s} \propto \sqrt{T}$

But the average velocity is zero.

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The specific resistance of all metals is most affected by :

Temperature

Pressure

Degree of illumination

Applied magnetic field

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Explanation

With rise in temperature specific resistance increases

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The positive temperature coefficient of resistance is for :

Carbon

Germanium

Copper

An electrolyte

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Explanation

For metallic conductors, temperature co-efficient of resistance is positive.

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The electric intensity E, current density j and specific resistance k are related to each other by the relation :

E = j/k

E = jk

E = k/j

k = jE

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Explanation

Specific resistance $k = \frac{E}{j}$

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The resistance of a wire of uniform diameter d and length L is R. The resistance of another wire of the same material but diameter 2d and length 4L will be :

R/2

R/4

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Explanation

$R \propto \frac{l}{A} \propto \frac{l}{d^{2}}$ ⇒ $\frac{R_{1}}{R_{2}} = \frac{l_{1}}{l_{2}} \times {(\frac{d_{2}}{d_{1}})}^{2} = \frac{L}{4 L} {(\frac{2 d}{d})}^{2} = 1$

⇒ R₂ = R₁ = R.

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There is a current of 1.344 amp in a copper wire whose area of cross-section normal to the length of the wire is 1 mm². If the number of free electrons per cm³ is 8.4 × 10²², then the drift velocity would be :

1.0 mm/sec

1.0 m/sec

0.1 mm/sec

0.01 mm/sec

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Explanation

$v_{d} = \frac{i}{n A e} = \frac{1 .344}{10^{- 6} \times 1 .6 \times 10^{- 19} \times 8 .4 \times 10^{22} \times 10^{6}}$

$= \frac{1 .344}{10^{3} \times 1 .6 \times 8 .4} = 0 .0001 m / s = 0.1 m m / s$

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