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Physics NEET Questions — Free MCQ Practice

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A coil of resistance 400 $Ω$ is placed in a magnetic field. If the magnetic flux $ϕ (W b)$ linked with the coil varies with time t (sec) as $ϕ = 50 t^{2} + 4 .$

The current in the coil at t=2s is

A.

0.5A

B.

0.1A

C.

2A

D.

1A

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Explanation

Induced emf of coil E = ${|- \frac{d ϕ}{d t}|}_{t}$

Given, $ϕ = 50 t^{2} + 4 a n d R = 400 Ω$

$E = {|- \frac{d ϕ}{d t}|}_{t = 2}$

$= {|100 t|}_{t = 2} = 200 V$

Current in the coil

$i = \frac{E}{R} = \frac{200}{400}$

= $\frac{1}{2} = 0.5 A$

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A conducting circular loop is placed in a uniform magnetic field, B=0.025 T with its plane perpendicular to the loop.The radius of the loop is made to shrink at a constant rate of 1 $m m s^{- 1}$ .The induced emf when the radius is 2cm, is

A.

$2 πμ V$

B.

$πμ V$

C.

$\frac{π}{2} μ V$

D.

$2 μ V$

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Explanation

Magnetic flux $ϕ = B \cdot A$

= $B \cdot {πr}^{2}$

Induced emf, $|e| = \frac{d ϕ}{d t} = B π 2 r \frac{d r}{d t}$

$= 0.025 \times π \times 2 \times 2 \times 10^{- 2} \times 1 \times 10^{- 3}$

= $πμV$

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A condenser of capacity C is charged to a potential difference of $V_{1} .$ The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to $V_{2}$ is

A.

${(\frac{C (V_{1} - V_{2})^{2}}{L})}^{\frac{1}{2}}$

B.

$\frac{C (V_{1}^{2} - V_{2}^{2})}{L}$

C.

$\frac{C (V_{1}^{2} + V_{2}^{2})}{L}$

D.

${(\frac{C (V_{1}^{2} - V_{2}^{2})}{L})}^{\frac{1}{2}}$

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Explanation

$Charge on the condenser at any instant q = q_{\circ} Cosωt where : ‐ ω = \frac{1}{\sqrt{LC}} Coswt = \frac{q}{q_{\circ}} = \frac{{CV}_{2}}{{CV}_{1}} Coswt = \frac{V_{2}}{V_{1}} q = q_{\circ} Cosωt I = \frac{dq}{dt} = - q_{\circ} Sinωt \times ω = - q_{\circ} \cdot ω \sqrt{q - {Cos}^{2} ωt} |I| = \frac{{CV}_{1}}{\sqrt{LC}} \cdot \sqrt{1 - \frac{V_{2}^{2}}{V_{1}^{2}}} = {[\frac{C (V_{1}^{2} - V_{2}^{2})}{L}]}^{1 / 2}$

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A rectangular, a square, a circular and an elliptical loop, all in the (x-y) plane, are moving out of a uniform magnetic field with a constant velocity, $\vec{v} = v \hat{i} .$ The magnetic field is directed along the negative z-axis direction. The induced emf, during the passage of these loops, out of the field region, will not remain constant for

A.

the rectangular, circular and elliptical loops

B.

the circular and the elliptical loops

C.

only the elliptical loop

D.

any of the four loops

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Explanation

Area coming out per second from the magnetic field is not constant for elliptical and circular loops, so induced emf, during the passage of these loops, out of the field region will not remain constant for the circular and the elliptical loops.

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a long solenoid has 500 turns. When a current of 2 A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4 \times 10^{- 3}$ Wh. The self-inductance of the solenoid is

A.

2.5 h

B.

2.0 H

C.

1.0 H

D.

4.0 H

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Explanation

Inductance of a coil is numerically equal to the emf induced in the coil when the current in the coil changes at the rate of 1 $A s^{- 1}$ . If I is the current flowing in the circuit, then flux linked with the circuit is observed to be proportional to i, i.e.,

$ϕ \propto I o r ϕ = L I . . . (i)$

where L is called the self-inductance or coefficient of self-inductance or simply inductance of the coil.

Net flux through solenoid,

$ϕ = 500 \times 4 \times 10^{- 3} = 2 W b o r 2 = L \times 2 [a f t e r p u t t i n g v a l u e s i n E q .] o r L = 1 H$

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A circular disc of radius 0.2 m is placed in a uniform magnetic field of induction $\frac{1}{π}$ $(\frac{W b}{m^{2}})$ in such a way that its axis makes an angle of $60^{°}$ with $\vec{B}$ . The magnetic flux linked with the disc is

A.

0.02 Wb

B.

0.06 Wb

C.

0.08 Wb

D.

0.01 Wb

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A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled and the wire radius halved, the electrical power dissipated would be –

A.

halved

B.

the same

C.

doubled

D.

quadrupled

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Explanation

2. As number of turns are quadrupled, the induced emf will increase four times. Also, resistance of

coil increases sixteen times. Hence power $(\frac{ε^{2}}{R})$ will not change.

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A coil having number of turns N and cross-sectional area A is rotated in a uniform magnetic field B with an angular velocity $ω$ . The maximum value of the emf induced in it is –

A.

$\frac{NBA}{ω}$

B.

$NBAω$

C.

$\frac{NBA}{ω^{2}}$

D.

${NBAω}^{2}$

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Explanation

2. The flux linking with the coil at any instant t is given as $Φ = NBA \cos ωt$

$∴ ε = - \frac{dΦ}{dt} = NBAωsin ωt$

Therefore, the maximum value of emf is $ε_{\max} = NBAω$

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A series combination of inductance (L) and resistance (R) is connected to a battery of emf E. The final value of current depends on –

A.

L and R

B.

E and R

C.

E and L

D.

E, L, and R

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Explanation

2. Initially, the induced emf (or back emf) is there due to the growth of current through the circuit. The inductance behaves as an open-circuit. Once the current up to its final value $I_{0}$ , there occurs no more change in the current. The back emf induced in the inductance reduces to zero. It behaves like a short-circuit. Hence the final value of the current is $I_{0} = \frac{E}{R},$ which depends only on E and R.

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A metal rod moves at a constant velocity in a direction perpendicular to its length. A constant, uniform magnetic field exists in space in a direction perpendicular to the rod as well as its velocity. Select the correct statement (s) from the following :

A.

The entire rod is at the same electric potential

B.

There is an electric field in the rod

C.

The electric potential is highest at the center of the rod and decreases towards its ends

D.

The electric potential is lowest at the center of the rod and increases towards its ends.

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Explanation

2. According to Faraday’s law, an induced emf is set up on the rod whose magnitude is Blv. Thus,

an electric field is generated in the rod. The electric potential varies uniformly along the rod.

Physics MCQs for NEET — Practice Questions with Answers

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