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A parallel plate air capacitor has a capacitance C. When it is half filled with a dielectric of dielectric constant 5, the percentage increase in the capacitance will be

A. 200% B. 33.30% C. 400% D. 66.60%

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Explanation

$C_1 = { A \varepsilon_0 \over d/10 } $ $C_2 = { A \varepsilon_0 \over d/2 } \Rightarrow C_5 = { 5C \over 3 } $ $ \therefore Percentage increase in capacitance = { C_5 - C \over C } \times 100 \% $

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The capacities of three capacitors are in the ratio 1 : 2 : 3. Their equivalent capacity when connected in parallel is 60/11 F .more then that when they are connected in series. The individual capacitors are of capacities in $ \mu F$

A. 4,6,7 B. 1,2,3 C. 1,3,6 D. 2,3,4

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Explanation

Theory base question

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What is the least count of the vernier callipers ?

A. Smallest division on the vernier scale. B. Difference of the smallest division on the mai scale and the smallest division on the vernier scale. C. sum of the smallest division on the main scale and the smallest division on the vernier scale. D. smallest division on the main scale

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Explanation

If main scale division = M and vernier scale division = V 9M = 10 V (10-1) M = 10V 10M - M = 10V 10 (M - V)= M, M,(M-V) = M/10 = least count.

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What is the least count of commonly available vernier ?

A. 0.01 cm B. 0.001 cm C. 0.0001 cm D. 0.1 cm

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Explanation

Least count = M /n = 1mm/10 = 0.1 mm = 0.01cm

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When the zero mark on the vernier scale lies towards the left side of the zero mark of the main scale, when the jaws are connect, then what will be the zero error ?

A. zero error is positive B. zero error is negative C. zero correction is positive D. zero error does not exist

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Explanation

Here zero error is positive, so zero. correction is negative, as zero correction = - (zero error)

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When the zero mark on the vernier scale lies towards the right side of the zero mark of the main scale, when the jaws are in contact, then what will be the zero error ?

A. zero correction in positive B. zero correction is negative C. zero error in positive D. zero error does not exist

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Explanation

Here zero error is negative, so zero correction is positive.

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If observed reading is OR, corrected reading is CR, zero error in ZE and zero correction in ZC, then what will be the possibility ?

A. CR = OR + ZC and ZE = CR-OR B. CR = OR + ZE and ZC = CR-OR C. CR = OR - ZC and ZE = OR-CR D. CR = OR - ZE and ZC = CR-OR

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Explanation

Corrected reading = Observed reading - zero error $ \Rightarrow CR = OR - ZE $ $ \Rightarrow CR = OR + ZC $ $ \Rightarrow ZC = CR - OR $

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When the jaws of a standard vernier are together, the 6th vernier scale division coincides withthe 6th main scale division, then what in the zero error ?

A. -0.4 mm B. +0.6 mm C. -0.6 mm D. +0.4 mm

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Explanation

vernier divisions are smaller then the main scale dividions (9M = 10V), the zero of the vernier must be on the right side of the zero of the main scale. Here zero error is positive.$ \Rightarrow Zero error = 6M -6V = 6(M_V ) = 6 (0.1 mm) = +0.6 mm $

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When the jaws of a standard vernier are together, the 6th main scale division coincides with the 7th vernier scale division, then what is the zero error ?

A. -0.7 mm B. +0.3 mm C. -0.3 mm D. +0.7 mm

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Explanation

Zero erroe = 6M -7V = (7M -&V) -M = 7 (0.1 mm ) - 1mm = -0.3 mm

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In an anusualvernier, 9 vernier scale divisions coincide with 8 main scale division, then what is the least count of the vernier ?

A. 8/9 mm B. 1/9 mm C. 1/ 17 mm D. 1/8 mm

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Explanation

8M = 9V \Rightarrow 9M - M = V 9(M-V) = M or (M -V ) = M/ 9 = 1 /9 mm

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