Physics MCQs for NEET — Practice Questions with Answers

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Which of the following statements are true regarding Bohr's model of hydrogen atom

(I) Orbiting speed of electron decreases as it shifts to
discrete orbits away from the nucleus

(II) Radii of allowed orbits of electron are proportional to the cube of principal quantum number

(III) Frequency with which electrons orbits around the nucleus in discrete orbits is inversely proportional to the principal quantum number

(IV) Binding force with which the electron is bound to the nucleus increases as it shifts to outer orbits
Select correct answer using the codes given below
Codes :

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Explanation

(a) Orbital speed varies inversely as the radius of the orbit. Energy increases with the increase in quantum number.

 For electron moving in nth orbit of H-atom the angular velocity is proportional to 

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Explanation

(d)  Radius of nth orbit, rn α 1n2

Velocity of electron, vn α 1n

 Angular velocity, ωn=vnrnωn α 1n3

The energy of electron in first excited state of H-atom is -3.4 eV its kinetic energy is

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Explanation

(b) Kinetic energy = |Total energy|

Which of the following phenomena suggests the presence of electron energy levels in atoms?

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Explanation

(c) Spectral lines result from emission or absorption of energy due to difference in energy levels of electrons.

Which of the following spectral series in hydrogen atom give spectral line of 4860 Å 

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Explanation

(b) For Balmer series :

 λmin=3648 Aoλmax=6563 Ao

When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: h = 6.6×10-34 J-s6.6)

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Explanation

(c) Change in the angular momentum

L=L2-L1=n2h2π-n1h2πL=h2π(n2-n1)=6.6×10-342×3.14(5-4)=1.05×10-34 J-s

The concept of stationary orbits was proposed by

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Explanation

(a) The concept of stationary orbits was proposed by Neil Bohr.

The time of revolution of an electron around a nucleus of charge Ze in nth Bohr orbit is directly proportional to

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Explanation

(b) T=2πrv  ; r = radius of nth orbit= n2h2πmZe2

v = speed of e- in nth orbit = ze22ε0nh

T=4ε02n3h3mZ2e4Tn3Z2

If R is the Rydberg’s constant for hydrogen the wave number of the first line in the Lyman series will be

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Explanation

(b) For Lyman series

v¯=1λ=R112-1n2  here n =2, 3, 4, 5......

For first line 

v¯=1λ=R112-122 v¯=R1-14=3R4

In hydrogen atom, if the difference in the energy of the electron in n =2 and n = 3 orbits is E, the ionization energy of hydrogen atom is 

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Explanation

(b) Energy E=K1n12-1n22 (K = constant)
n1 = 2 and n2 = 3, so E=K122-132=K536
For removing an electron n1 = 1 to n2 = 
Energy E1=K1=365E=7.2 E
 Ionization energy = 7.2 E

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