Physics MCQs for NEET — Practice Questions with Answers

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If the binding energy of the deutrium is 2.23 MeV.
The mass defect given in a.m.u. is 

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Explanation

(d) Mass defect m=2.23931 = 0.0024.

Which of the following has the mass closest in value to that of the positron 

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Explanation

(b) Positron is the antiparticle of electron.

Size of nucleus is of the order of

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Explanation

(b) Size of the nucleus is of the order of 10-15 m

For effective nuclear forces, the distance should be

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Explanation

(c) Nuclear force works in the range of 10-15 m

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particle) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV) :

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Explanation

(a) B.E. = mc2=21.0087+1.0073-4.0015×931.5=28.4 MeV

Atomic power station at Tarapore has a generating capacity of 200 MW. The energy generated in a day by this station is

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Explanation

(d) Energy / day = 200×106×24×3600

=2×2.4×3.6×1012=1728×1010 J

One microgram of matter converted into energy will give

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Explanation

(c) E=mc2=10-6×3×1082=9×1010 J

The average binding energy per nucleon in the nucleus of an atom is approximately 

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Explanation

(c) The average binding energy per nucleon = 8 MeV

The binding energy of deuteron H12 is 1.112 MeV per nucleon and an α-particle He24 has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction H12+H12He24+Q, the energy Q released is

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Explanation

(c) Mass of H21 = 2.01478 a.m.u
Mass of He42 = 4.00388 a.m.u
Mass of two deuterium = 2×0.1478=4.02956
Energy equivalent to 2H21

= 4.02956×1.112 MeV=4.48 MeV

Energy equivalent to He42
= 4.00388×7.047 MeV = 28.21 MeV
Energy released = 28.21-4.48 = 23.73 MeV = 24 MeV

Binding energy of a nucleus is

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Explanation

(c) Energy released while forming a nucleus is known as binding energy (by definition).

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