A light bulb is rated at 100 W for a 220 V supply. The RMS current through the bulb is approximately:
Given \(P = 100 W\) and \(V_{rms} = 220 V\). We know \(P = I_{rms} V_{rms}\). Therefore, \(I_{rms} = P / V_{rms} = 100 W / 220 V \approx 0.454 A\). This is directly from Example 7.1 (c).