The de Broglie wavelength ($\lambda$) of a particle with momentum ($p$) is given by the relation:
The context explicitly states: 'From Chapter 11, we have $\lambda = h/p$, where $p$ is the magnitude of the electron’s momentum.' and also in the 'DUAL_NATURE_OF_RADIATION_AND_MATTER' chapter: 'The de Broglie wavelength ($\lambda$) associated with a moving particle is related to its momentum $p$ as: $\lambda = h/p$.'