Physics MCQs for NEET — Practice Questions with Answers

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The household line voltage in India is typically 220 V. This value represents the:

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Explanation

The context explicitly mentions, 'It is customary to measure and specify rms values for ac quantities. For example, the household line voltage of 220 V is an rms value'. This confirms that such general ratings refer to RMS values.

If the RMS voltage of a household supply is 220 V, what is the peak voltage ($V_m$) of the source?

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Explanation

The text provides the calculation: '$V_m = \sqrt{2} V = (1.414)(220 V) = 311 V'$. This shows how to convert from RMS voltage to peak voltage.

An AC circuit with RMS voltage $V$ and RMS current $I$ consumes an average power $P$. Which of the following expressions is analogous to DC power ($P = I^2R$)?

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Explanation

The text states: 'In terms of I, the average power, denoted by P is $P = I_m^2 R/2 = I^2 R$'. It also mentions, 'In terms of rms values, the equation for power [Eq. (7.7)] and relation between current and voltage in ac circuits are essentially the same as those for the dc case.' This supports $P=I^2R$ as the equivalent expression.

A light bulb is rated at 100 W for a 220 V supply. The '220 V' represents the:

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Explanation

As stated in 'POINTS TO PONDER 1.', 'When a value is given for ac voltage or current, it is ordinarily the rms value. The voltage across the terminals of an outlet in your room is normally 240 V. This refers to the rms value of the voltage.' Similarly, the 220V rating for the bulb in example 7.1 is an RMS value.

For a light bulb rated at 100 W for a 220 V supply, what is the resistance of the bulb?

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Explanation

From Example 7.1(a): 'We are given P = 100 W and V = 220 V. The resistance of the bulb is $R = V^2 / P = (220 V)^2 / 100 W = 48400 / 100 \Omega = 484 \Omega$'.

What is the RMS current through the light bulb from the previous question (100 W, 220 V supply)?

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Explanation

From Example 7.1(c): 'Since, $P = I V$, then $I = P / V = 100 W / 220 V = 0.454 A$'.

Why is the average current over one complete cycle of a sinusoidal AC current zero?

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Explanation

The context states: 'Thus, the sum of the instantaneous current values over one complete cycle is zero, and the average current is zero.' This is because for every positive value, there is a corresponding negative value.

The RMS value of an AC voltage ($V$) is related to its amplitude ($V_m$) by the formula:

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Explanation

The table for physical quantities and remarks states: 'rms voltage $V = \frac{V_m}{\sqrt{2}}$, $V_m$ is the amplitude of the ac voltage.' This directly provides the relationship.

According to the context, how is the AC ampere (RMS value) defined?

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Explanation

The 'POINTS TO PONDER 4.' section states: 'Joule heating is such a property, and there is one ampere of rms value of alternating current in a circuit if the current produces the same average heating effect as one ampere of dc current would produce under the same conditions.'

Which of the following statements about power in an AC circuit is incorrect?

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Explanation

From 'POINTS TO PONDER 2.', 'The power rating of an element used in ac circuits refers to its average power rating.' From 'POINTS TO PONDER 3.', 'The power consumed in an ac circuit is never negative.' And from the example 7.2 explanation, 'Thus, the average power supplied to an inductor over one complete cycle is zero.' However, Case (iv) under power factor discusses LCR series circuit at resonance: 'At resonance Xc – XL= 0, and φ = 0. Therefore, cos φ = 1 and P = I^2Z = I^2R. That is, maximum power is dissipated in a circuit (through R) at resonance.' Thus, option 4 is incorrect.

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