A geostationary satellite orbits around the earth in a circular orbit of radus 3600 km the time period of a satellite orbiting a few hundred kilometers above the earth’s surface (Rearth = 6400 km) will approximately be = ………...h
$ {T_2 \over T_1 } = \left( {r_1 \over r_2} \right ) ^ {3/2} \Rightarrow T_2 = 24 \left( {6400 \over 3600} \right)^{3/2} = 2hours $

