Physics MCQs for NEET — Practice Questions with Answers

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NEET 2025

Two cities X and Y are connected by a regular bus service with a bus leaving in either direction every $T$ min. A girl is driving scooty with a speed of 60 km/h in the direction X to Y notices that a bus goes past her every 30 minutes in the direction of her motion, and every 10 minutes in the opposite direction. Choose the correct option for the period $T$ of the bus service and the speed (assumed constant) of the buses.

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Explanation

$\dfrac{vT}{v-60} = 30$, $\dfrac{vT}{v+60} = 10$. Dividing: $\dfrac{v+60}{v-60} = 3\Rightarrow v = 120$ km/h; then $T = 15$ min.

NEET 2025

A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of $60^\circ$ with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (take $g = 10\ \text{m/s}^2$):

60° 5 m, 20 kg
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Explanation

Rod makes $30^\circ$ with floor. Torque about the floor end: $N_w\,l\sin30^\circ = mg\,\tfrac{l}{2}\cos30^\circ\Rightarrow N_w = \dfrac{mg}{2}\cot30^\circ$... giving wall normal $= 100\sqrt3$ N. Friction $f = N_w = 100\sqrt{3}$ N.

NEET 2025

In an oscillating spring mass system, a spring is connected to a box filled with sand. As the box oscillates, sand leaks slowly out of the box vertically so that the average frequency $\omega(t)$ and average amplitude $A(t)$ of the system change with time $t$. Which one of the following options schematically depicts these changes correctly?

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Explanation

As sand leaks, mass $m$ decreases, so $\omega = \sqrt{k/m}$ increases. The adiabatic invariant $E/\omega$ is constant and $E = \tfrac12 kA^2$, giving $A\propto\sqrt{\omega}$, so $A$ also increases.

NEET 2025

A balloon is made of a material of surface tension $S$ and its inflation outlet (from where gas is filled in it) has small area $A$. It is filled with a gas of density $\rho$ and takes a spherical shape of radius $R$. When the gas is allowed to flow freely out of it, its radius $r$ changes from $R$ to 0 (zero) in time $T$. If the speed $v(r)$ of gas coming out of the balloon depends on $r$ as $r^a$ and $T\propto S^\alpha A^\beta \rho^\gamma R^\delta$ then:

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Explanation

Excess pressure $\Delta P = \tfrac{4S}{r}$; Bernoulli gives $v = \sqrt{8S/(\rho r)}\propto r^{-1/2}$ so $a=-\tfrac12$. From $Av = -4\pi r^2\tfrac{dr}{dt}$, integrating $r$ from $R$ to 0 gives $T\propto R^{7/2}A^{-1}S^{-1/2}\rho^{1/2}$, i.e. $\alpha=-\tfrac12,\beta=-1,\gamma=\tfrac12,\delta=\tfrac72$.

NEET 2025

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at $x = 0.1$ cm when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is:

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Explanation

LC $= 1\,\text{MSD} - 1\,\text{VSD} = 0.1 - 0.09 = 0.01$ cm. Observed $= 5 + 8(0.01) = 5.08$ cm. Positive zero error $= +0.10$ cm. Corrected $= 5.08 - 0.10 = 4.98$ cm.

NEET 2025

A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is:

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Explanation

The displacement current produces a magnetic field that is non-zero everywhere and is maximum on the cylindrical surface joining the plate edges (at $r = R$).

NEET 2025

An unpolarized light beam travelling in air is incident on a medium of refractive index 1.73 at Brewster's angle. Then—

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Explanation

$\tan\theta_B = 1.73 = \sqrt3\Rightarrow\theta_B = 60^\circ$. At Brewster's angle the reflected light is completely (plane) polarized and the angle of reflection equals $\theta_B = 60^\circ$.

NEET 2025

Two identical charged conducting spheres A and B have their centres separated by a certain distance. Charge on each sphere is $q$ and the force of repulsion between them is F. A third identical uncharged conducting sphere is brought in contact with sphere A first and then with B and finally removed from both. New force of repulsion between spheres A and B (radii of A and B are negligible compared to the distance of separation so that for calculating force between them they can be considered as point charges) is best given as:

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Explanation

After touching A: $q_A = q/2$. Touching B (now $q/2 + q = 3q/2$ shared): $q_B = 3q/4$. New $F\propto\left(\tfrac{q}{2}\right)\left(\tfrac{3q}{4}\right) = \tfrac{3}{8}q^2$, i.e. $\dfrac{3F}{8}$.

NEET 2025

A container has two chambers of volumes $V_1 = 2$ litres and $V_2 = 3$ litres separated by a partition made of a thermal insulator. The chambers contain $n_1 = 5$ and $n_2 = 4$ moles of ideal gas at pressures $p_1 = 1$ atm and $p_2 = 2$ atm, respectively. When the partition is removed, the mixture attains an equilibrium pressure of:

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Explanation

Internal energy conserved $\Rightarrow P_f = \dfrac{p_1V_1 + p_2V_2}{V_1+V_2} = \dfrac{1(2)+2(3)}{5} = \dfrac{8}{5} = 1.6$ atm.

NEET 2025

A particle of mass $m$ is moving around the origin with a constant force $F$ pulling it towards the origin. If Bohr model is used to describe its motion, the radius $r$ of the $n^{th}$ orbit and the particle's speed $v$ in the orbit depend on $n$ as:

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Explanation

$F = \dfrac{mv^2}{r}$ (constant) and $mvr = \dfrac{nh}{2\pi}$. Eliminating: $v^3\propto n\Rightarrow v\propto n^{1/3}$ and $r\propto \dfrac{n}{v}\propto n^{2/3}$.

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