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Physics MCQs for NEET — Practice Questions with Answers

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The magnetic field due to a short magnet at a point on its axis at a distance x cm from the middle point of the magnet is 200 gauss. The magnetic field at a point on the neutral axis at a distance xcm from the middle of the magnet is gauss.

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Explanation

$ on the axis B axis = { 2m \over x^3 } $ $ 200 gauss = { 2M \over x^3 } $ $ 100 gauss= { M \over x^3 } $ 100 gauss = Bequator

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A bar magnet having a magnetic moment of $ 2 \times 10^ 4 J T^{-1} $ is free to rotate in a horizontal plane. A horizontal magnetic field $ B = 6 \times 10^{-4} $ Tesla exists in the space. The workdone in taking the magnet slowly from a direction parallel to the field to a direction $60^ \circ $ from the field is

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Explanation

$ W = MB( 1 -cos \theta ) $ $ = 2 \times 10^4 \times 6 \times 10^{-4} (1 - cos 60 ^\circ) $ = 6 joule

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A magnet of length 0.1 m and pole strength $ 10^ { -4 } A.m $ is kept in a magnetic field of 30 tesla at an angle of $30 ^ \circ $ . The couple acting on it is………. $ \times 10^ {-4 } $ Joule.

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Explanation

$ \tau = MB sin \theta $ $ = m ( 2l ) \times B sin \theta $ $ = 10^{-4} \times 0.1 \times 39 sin ^\circ $ $ = 1.5 \times 10^{-4} J $

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In the case of bar magnet, lines of magnetic induction

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Explanation

In the case of a bar magnet, lines of magnetic induction (magnetic field lines) run continuously from the North pole to the South pole outside the magnet, and from the South pole to the North pole inside the magnet. This creates a closed loop, ensuring that the magnetic field lines are continuous.

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A small bar magnet of moment M is placed in a uniform field of H. If magnet makes anangle of $ 30^ \circ $ with field, the torque acting on the magnet is

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Explanation

$ \tau = MB sin \theta $ $ = MH sin 30 ^ \circ $ $ = { MH \over 2 } $

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The effective length of a magnet is 31.4 cm and its pole strength is 0.5 A.m. The magnetic moment, if it is bent in the form of a semicircle will be…….$Amp.m^2$.

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Explanation

$ 0.1 Amp m^2$

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A bar magnet of length 10 cm and having the pole strength equal $ 00.1 \times 10^{-3} $ to is kept ina magnetic field having magnetic induction (B) equal to $4 \pi \times 10^ {-3 } $ tesla. It makes an angle of 300 with the direction of magnetic induction. The value of the torque acting on the magnet is ...................... Joule.

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Explanation

$ torque \tau = MH _H sin \theta $ $ = 2 \pi \times 10^{-7} J$

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A small bar magnet has a magnetic moment $ 1.2 A.m^ 2$. The magnetic field at a distance 0.1 m on its axis will be…….tesla.

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Explanation

$ B = { \mu0 \over 4 \pi } { 2M \over d^3 } $ $ = 2.4 \times 10^{-4} tesla $

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Force between two idential bur magnets whose centres are r meter apart is 4.8 N, when their axes are in the same line. If separation is increased to 2r, the force between them is reduced to

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Explanation

$ in magnetic dipole ,force \times {1 \over r^4 } $ $ { F_2 \over F_1 } = { r_1^4 \over r_2^4 } $ $ { F_2 \over 4.8 } = \left( { r_1 \over 2 r_1} \right)^4 $ $ = 0.3 Newton $

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A magnet of magnetic moment $ 50 \uparrow A.m^2 $ is placed along the X-axis in a mag. Field $ \vec B = ( 0.5 \uparrow + 3.0 \hat J ) $ Tesla. The torque acting on the magnet is ……... N.m.

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Explanation

$ \tau = \vec M \times \vec B $ $ = 150 \hat K N.m$

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