NEET Practice Questions (MCQs) with Answers & Solutions

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In a common base amplifier the phase difference between the input signal voltage and the output voltage is

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Explanation

(a) In CB amplifier Input and output voltage signal are in same phase.

In NPN transistor the collector current is 10 mA. If 90% of electrons emitted reach the collector, then

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Explanation

(b) As 90% of the electrons reach the collector, then

90% of emitter current = 10 mA

emitter current = 1090×100=11.1 mA

In a transistor in CE configuration, the ratio of power gain to voltage gain is 

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Explanation

(d) For CE configuration voltage gain =β×RL/Ri

Power gain = β2×RL/RiPower gainVoltage gain=β

The following truth table corresponds to the logic gate

A  0  0  1  1
B  0  1  0  1
X  0  1  1  1

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Explanation

(b) For ‘OR’ gate X = A+B   i.e. 0+0=0, 0+1=1, 1+0=1, 1+1=1

A truth table is given below. Which of the following has this type of truth table 

A  0  1  0  1
B  0  0  1  1
y  1  0  0  0

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Explanation

(b) In 'NOR' gate Y=A+B¯, i.e.

 0+0¯=0¯=1, 1+0¯=1¯=00+1¯=1¯=0, 1+1¯=1¯=0

Boolean algebra is essentially based on 

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Explanation

(b) Boolean algebra is based on logic.

 The logic behind ‘NOR’ gate is that it gives

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Explanation

(a) The Boolean expression for 'NOR' gate is Y=A+B¯

i.e.   if  A = B = 0 (Low),   Y=0+0¯=0¯=1  (High)

A logic gate is an electronic circuit which 

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Explanation

(a) 

A gate has the following truth table 
P 1 1 0 0
Q 1 0 1 0
R 1 0 0 0

The gate is

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Explanation

(d) The Boolean expression for ‘AND’ gate is R=P·Q

 1·1 = 1,  1·0 = 0,  0·1 = 0,  0·0 = 0

What will be the input of A and B for the Boolean expression A+B¯·A·B¯=1

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Explanation

(a) The given Boolean expression can be written as

Y=A+B¯·A·B¯=A¯·B¯·A¯+B¯=A¯·A¯B¯+A¯B¯·B¯=A¯·B¯+A¯·B¯=A¯·B¯

A

B

Y

0

0

1

1

0

0

0

1

0

1

1

0

 

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