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The molecule having the smallest bond angle is
Bond angle decreases in the H2O > H2S > H2Se > H2Te.
In H3PO3
H3PO3 is
Here are two hydrogen atoms are attached to oxygen atoms.
Strong oxidising agent and strong reducing agents are respectively
Fluorine is strongest oxidising agent because of its highest reduction potential and HI is strong reducing agent due to large size of iodine atom and weak H-I bond which breaks easily to give hydrogen.
Oxide of a non-metal possesses the following characterstics.
(i) It is both a proton donor and proton acceptor
(ii) It is poor conductor of electricity
(iii) It reacts readily with basic and acidic oxides
(iv) It oxidises Fe at boiling point.
The oxide is
H2O is a proton donor and proton acceptor.Pure water is poor conductor of electricity. Water readily reacts with basic and acidic oxides.Water also oxidises Fe at boiling point.
A yellow metallic powder is burnt in a stream of fluorine to obtain a colourless gas X which is thermally stable and chemically inert. Its molecule has octahedral geometry. Another colourless gas Y with same constituent atoms as that of X is obtained when sulphur dichloride is heated with sodium fluoride. Its molecule has triangular pyramidal structure X and Y are
SF4 has trigonal pyramidal shape due to sp3d hybridisation. SF6 is octahedral due to sp3d2 hybridisation. Sulphur has S8 molecular geometry
In nitrogen family the H-M-H bond angle in the hybrides MH3 gradually becomes closer to 90o on going from N to Sb. This shows that gradually
The hybrides have a pyramidal or tetrahedral shape with a lone pair of electrons in on of the orbitals.The H-M-H bond angle is less than the original 109o28' tetrahedral bond angle(H-N-H in NH3 is 106o45') because of greater repulsion between lone pair and a bond pair than between two obnd pairs of electrons.Because electronegativity of M decreases from N to Bi, the bond pair lie farther away from the central atom, and the lone pair causes greater distortion of bond angle.
Thus H-P-H bond in PH3 is 94o , while in AsH3 and SbH3 it is about 91.8o and 91.3o respectively(closer to 90o). This suggests that orbitals used for bonding are closer to pure p-orbitals.
The volume of 2M NaOH required to convert 12 grams of NaH2PO4 [M=120gm mol-1] into Na3PO4 is
The reaction is
Assertion : In trimethyalamine (N(CH3)3), the nitrogen has a pyramidal geometry, wheres in trisilylamine (N(SiH3)3), it has a planer geometry.
Reason : In trimethylamine, nitrogen shows sp3 hybridization while in trisilyamine it shows sp2 hybridization.
In trimethylamine, nitrogen shows sp3 hybridization therefore trimethylamine has a pyramidal geometry while in trisilyamine it shows sp2 hybridization resulting in a planer square.
Assertion : Most of the known noble gas compounds are those of xenon.
Reason : The ionisation enthalpy of xenon is very close to that of oxygen.
Most of the known noble gas compounds are those of xenon because the ionization enthalpy of xenon is very close to that of oxygen.
Assertion : ClF3 exists bul FCl3 does not.
Reason : FCl3 is not formesd due to greater steric hinderance by the larger Cl atoms.
ClF3 exists bul FCl3 does not because FCl3 is not formed due to greater steric hinderance by the larger Cl atoms.
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